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harkovskaia [24]
2 years ago
8

If the temperature outside was 63 at 5:00 pm but it fell 21 degrees by 10:00 pm what is the temperature at 10:00 pm? Write the e

quation and solve it
Mathematics
2 answers:
Naily [24]2 years ago
8 0
It would be 42 degrese

r u using it 4 kahn XD

igomit [66]2 years ago
5 0
X = temperature at 5:00 (63)
Y = Degrees dropped (21)
S = temperature at 10:00

x-y=s
63-21=s

S=42
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Given the information below, write the equation in Standard Form.
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Answer:

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Step-by-step explanation:

The standard form of the equation of a parabola is (y - k)² = 4p (x - h), where

  • The vertex of the parabola is (h , k)
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∵ The vertex of the parabola is (3 , -2)

∴ h = 3 and k = -2

∵ The focus is (5 , -2)

∴ h + p = 5

- Substitute h by 3 to find p

∵ 3 + p = 5

- Subtract 3 from both sides

∴ p = 2

∵ The standard form of the equation of the parabola is (y - k)² = 4p (x - h)

- Substitute the values of h , k , and p in the equation

∴ (y - -2)² = 4(2) (x - 3)

∴ (y + 2)² = 8 (x - 3)

The standard form of the equation of the parabola is (y + 2)² = 8 (x - 3)

3 0
2 years ago
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lianna [129]
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3 years ago
Write the following in order from smallest to largest: 3\12, 0.146, 5\7, 0.279
Brrunno [24]

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Step-by-step explanation:

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Sliva [168]

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3 years ago
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2 years ago
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