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MrMuchimi
3 years ago
8

There are 4 boys and 2 girls from the seventh grade and 3 boys and 5 girls from the eighth grade on the soccer team. Coach Foste

r will pick one captain from each grade. What is the probability that both captains will be girls? Type your answer as a simplified fraction.
Mathematics
1 answer:
hodyreva [135]3 years ago
5 0
1/2 because there is 7 girls and 7 boys in total
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The length of a paper clip chain is directly proportional to the number of paper clips. If a chain with 65 paper clips has a len
Ghella [55]

<u>Answer:</u>

The length of a paper clip chain is directly proportional to the number of paper clips. If a chain with 65 paper clips has a length of 97.5 inches then the length of chain with 14 paper clips is 21 inches.

<u>Solution:</u>

Given that the length of a paper clip chain is directly proportional to the number of paper clips. Directly propotional means when the length of paper clip increases, then the number of paper clips also increases in same ratio.

Hence, by above definition, we get  

\frac{l_{1}}{l_{2}} = \frac{n_{1}}{n_{2}}  ------- eqn 1

From question, for a chain with 65 paper clips has a length of 97.5 inches, we get  

l_{1} = 97.5 \text { and } n_{1} = 65

Similarly, for a chain with 14 paper clips with length to be found, we get  

n_{2}=14 \text { and } l_{2} = ?

Now by using eqn 1, we can calculate the length of 14 paper clips  is,

\frac{97.5}{65}=\frac{l_{2}}{14}

Rearranging the terms we get,

l_{2 }= \frac{97.5 \times 14}{65}

l_{2}=21 \text { inches }

Hence the length of chain with 14 paper clips is 21 inches.

3 0
3 years ago
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I’m sorry, but I’m also lost looking at that .

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8 0
3 years ago
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(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate
Anon25 [30]

Answer:

The margin of error (E)  =0.49

Step-by-step explanation:

Given,

 mean \bar{x}=6.88

 standard deviation \sigma=1.90

 sample size n=41

90\% \quad \text{confidence interval}

Critical value =\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]  

                                                =1-0.90

                                        \Rightarrow \alpha=0.1

Critical value =\frac{z_{0.1}}{2}

                      =z_{0.05}

                      =1.645

The margin of error (E)  =\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }

                                       =1.645\times\frac{1.90}{\sqrt{41} }

                                       =0.49

Hence, The margin of error (E) =0.49

Complete question is attached in below.

                     

7 0
3 years ago
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