°°°4°°°2°°°-18°°°°°°38
•|
-3|°°°-12°°°30°°°°°-36
------------------------------'
°°°4°° -10 12°°°°° °°2
remainder=2
4 bowls of pasta would be served for twelve people.
4×3=12
Answer:
The total mechanical energy is 0.712 J.
Step-by-step explanation:
A blue 573 g mobile is moving on a metal rail. If on the mobile, the spring exerts a force to the right of modulus 0.85 N and in the indicated position the kinetic energy of the mobile-spring system is 0.47 J and its elastic potential energy is 0.242 J. Determine the mechanical energy of the system mobile-spring in the position shown as indicated in the figure.
The total mechanical energy is given by the sum of the kinetic energy and the potential energy.
Kinetic energy = 0.47 J
Potential energy = 0.242 J
The total mechanical energy is
T = 0.47 + 0.242 = 0.712 J
Answer:
6 (2)^ = 6
6 (2)^2 = 24
a = 24
b = 6
y-intercept: (0,6)
y-intercept =
Step-by-step explanation:
6(2)^x
6 (2)^0 = 6 (a number ^0 = 1, 6 times 1 = 6)
6 (2)^2 = 6 x 4 = 24
