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krok68 [10]
3 years ago
7

Suppose you start an annuity where you invent$2,000 at the beginning or each year and 4% interest is paid at the end of the year

Mathematics
2 answers:
dimulka [17.4K]3 years ago
7 0
I believe $80 dollars would be 4% of 2,000
viktelen [127]3 years ago
7 0
2000x 0.04 = 80
End of the year have to pay 80
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2. Continuous data are usually _____________________, but discrete data are usually ______________________.
Mrrafil [7]

Answer:

Measured and Counted.

Step-by-step explanation:

Continuous data are usually “Measured”, but discrete data are usually “Counted”.

The continuous data are the data that can be measured, for example, Height of children, time in the race, length of leaf, etc. In this case, the data is taken within the range. While the discrete data is the data that can be counted. For example, the number of employees in the office, the number of students in the school, the result of rolling dice, etc. In this case, the data is a fixed number. Accordingly, the continuous data is measurable and discrete data is countable.

7 0
3 years ago
You get in an elevator and go down 8 floors. You exit on the 16th floor. Write and solve an equation to find what floor you got
disa [49]
So floor that you started is x
go down 8 means -8
end on 16

so
x-8=16
add 8
x=24

started on 24
3 0
3 years ago
If (-5x^5) (a) = 25x^7 + 100x^5, find a
sweet-ann [11.9K]
(-5x^5)(a) = 25x^7 + 100x^5
<u>+5x^5                         +5x^5</u>
             a = 25x^7

4 0
3 years ago
Tyler took a total of 16 quizzes over the course of four weeks. How many weeks of school will Tyler have to attend this quarter
wlad13 [49]

Answer:

he will have to go one more week and all together it would be five weeks

Step-by-step explanation:

16/4=4

you need four more to get to 20, and if he does 4 quizzes a week he only needs one more week.

7 0
3 years ago
The length of a text messaging conversation is normally distributed with a mean of 2 minutes and a standard deviation of .5 minu
Phoenix [80]
Let x be a random variable representing the length of a text messaging conversation, then
P(x > 3) = 1 - P(x < 3) = 1 - P(z < (3 - 2)/0.5) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275
6 0
3 years ago
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