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bulgar [2K]
3 years ago
9

Vehicle a averages 14 miles per gallon of gasoline, and vehicle b averages 36 miles per gallon of gasoline. at these rates, how

many more gallons of gasoline does vehicle a need than vehicle b to make a 1,008-mile trip?
Mathematics
1 answer:
Elis [28]3 years ago
4 0

So first we need to find the amount of gallons that it would take for each vehicle to travel 1,008 miles. We can do this by multiplying and canceling units:

Vehicle A: \frac{1,008mi}{1}* \frac{gal}{14mi}=72gal

Vehicle B: \frac{1,008mi}{1}*\frac{gal}{36mi}=28gal

So we found that Vehicle A needs 72 gallons to make the trip, and Vehicle B needs 28 gallons to make the trip.

Let's find the difference:

72-28=44

Therefore, Vehicle A needs 44 more gallons of gasoline than Vehicle B to make the trip.

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Answer:

D. f(t) = 192,345(1.04)^t

Step-by-step explanation:

<em>I took the test and it was right. </em>

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3 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

I hope this helps. If I misunderstood the question let me know

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2 years ago
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Write an equation in​ slope-intercept form of the line that passes through the given point and is parallel to the graph of the g
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70 > 55 + t

Step-by-step explanation:

Given

Previous\ Time = 1\ hr\ 10\ mins

Current\ Time = 55\ mins

Required

Represent the additional time needed as an inequality

Convert the previous time to minutes

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<em />

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This can be rewritten as:

70 > 55 + t

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