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m_a_m_a [10]
3 years ago
12

Which of the following is not the graph of a function of x?​

Mathematics
1 answer:
Paraphin [41]3 years ago
6 0

Answer:

i think it's the third one

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How many units is 1 from -6 on a number line
iVinArrow [24]
Find this by subtracting the two terms and then finding the absolute value of the difference.

1-(-6)= 7
|7|= 7

Final answer: 7
8 0
4 years ago
Evaluate the expression for the given value of the variable.
blsea [12.9K]
Poiuytrewqasdfghklmn
5 0
3 years ago
Read 2 more answers
Which inequality represents the sentence? The difference of seven and two tenths and a number is more than twenty nine. 7. 2 - n
Slav-nsk [51]

The inequality which represent, the difference of seven and two tenths and a number is more than twenty-nine, is

7.2-n > 29

<h3>What is the inequality equation?</h3>

Inequality equation is the equation in which the two expressions are compared with greater than, less than or other inequality signs.

Inequality is represented with the greater then(<), less then(>) or with the other inequity signs like less than equal to \leq or greater than equal to \geq.

Tenth is written as the fractional part of the number 10. The value of one tenth is equal to 1/10 or 0.1.

The sentence given for the inequality expression is, that the differences of seven and two tenths, and a number is more than twenty-nine.

The number seven and two tenths can be written as,

7\dfrac{2}{10}

Suppose the unknown number is n.  Now, the differences of seven and two tenths, and this number (<em>n</em>) is more than twenty-nine.  The more than word means, the greater than sign for equation. Thus, it can be expressed as,

7\dfrac{2}{10}-n > 29\\\dfrac{72}{10}-n > 29\\7.2-n > 29

Hence, the inequality which represent, the difference of seven and two tenths and a number is more than twenty-nine, is

7.2-n > 29

Learn more about the inequality equation here:

brainly.com/question/17724536

7 0
3 years ago
In some gymnastics meets, the score given to a gymnast is the mean of the judges’ scores after the highest and lowest scores h
Allisa [31]

Using the median concept, the correct statement is given as follows:

Her median score does not change.

<h3>What is the median of a data-set?</h3>

The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile, also called the middle value the data-set, not being affected by outliers.

For this problem, the data-set is given as follows:

7.50, 7.50, 7.75, 7.75, 8.00, 8.00, 8.00, 10.00.

There are 8 scores, hence the median is the <u>mean of the 4th and the 5th</u> scores, as follows:

(7.75 + 8)/2 = 7.875.

Removing the extreme values, the data-set will be given by:

7.50, 7.75, 7.75, 8.00, 8.00, 8.00.

Then it has 6 scores, hence the median is the <u>mean of the 3th and the 4th</u> scores, as follows:

(7.75 + 8)/2 = 7.875.

Same median, hence the correct option is:

Her median score does not change.

More can be learned about the median of a data-set at brainly.com/question/23923146

#SPJ1

7 0
2 years ago
Match each vector operation with its resultant vector expressed as a linear combination of the unit vectors i and j.
Cloud [144]

Answer:

3u - 2v + w = 69i + 19j.

8u - 6v = 184i + 60j.

7v - 4w = -128i + 62j.

u - 5w = -9i + 37j.

Step-by-step explanation:

Note that there are multiple ways to denote a vector. For example, vector u can be written either in bold typeface "u" or with an arrow above it \vec{u}. This explanation uses both representations.

\displaystyle \vec{u} = \langle 11, 12\rangle =\left(\begin{array}{c}11 \\12\end{array}\right).

\displaystyle \vec{v} = \langle -16, 6\rangle= \left(\begin{array}{c}-16 \\6\end{array}\right).

\displaystyle \vec{w} = \langle 4, -5\rangle=\left(\begin{array}{c}4 \\-5\end{array}\right).

There are two components in each of the three vectors. For example, in vector u, the first component is 11 and the second is 12. When multiplying a vector with a constant, multiply each component by the constant. For example,

3\;\vec{v} = 3\;\left(\begin{array}{c}11 \\12\end{array}\right) = \left(\begin{array}{c}3\times 11 \\3 \times 12\end{array}\right) = \left(\begin{array}{c}33 \\36\end{array}\right).

So is the case when the constant is negative:

-2\;\vec{v} = (-2)\; \left(\begin{array}{c}-16 \\6\end{array}\right) =\left(\begin{array}{c}(-2) \times (-16) \\(-2)\times(-6)\end{array}\right) = \left(\begin{array}{c}32 \\12\end{array}\right).

When adding two vectors, add the corresponding components (this phrase comes from Wolfram Mathworld) of each vector. In other words, add the number on the same row to each other. For example, when adding 3u to (-2)v,

3\;\vec{u} + (-2)\;\vec{v} = \left(\begin{array}{c}33 \\36\end{array}\right) + \left(\begin{array}{c}32 \\12\end{array}\right) = \left(\begin{array}{c}33 + 32 \\36+12\end{array}\right) = \left(\begin{array}{c}65\\48\end{array}\right).

Apply the two rules for the four vector operations.

<h3>1.</h3>

\displaystyle \begin{aligned}3\;\vec{u} - 2\;\vec{v} + \vec{w} &= 3\;\left(\begin{array}{c}11 \\12\end{array}\right) + (-2)\;\left(\begin{array}{c}-16 \\6\end{array}\right) + \left(\begin{array}{c}4 \\-5\end{array}\right)\\&= \left(\begin{array}{c}3\times 11 + (-2)\times (-16) + 4\\ 3\times 12 + (-2)\times 6 + (-5) \end{array}\right)\\&=\left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle\end{aligned}

Rewrite this vector as a linear combination of two unit vectors. The first component 69 will be the coefficient in front of the first unit vector, i. The second component 19 will be the coefficient in front of the second unit vector, j.

\displaystyle \left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle = 69\;\vec{i} + 19\;\vec{j}.

<h3>2.</h3>

\displaystyle \begin{aligned}8\;\vec{u} - 6\;\vec{v} &= 8\;\left(\begin{array}{c}11\\12\end{array}\right) + (-6) \;\left(\begin{array}{c}-16\\6\end{array}\right)\\&=\left(\begin{array}{c}88+96\\96 - 36\end{array}\right)\\&= \left(\begin{array}{c}184\\60\end{array}\right)= \langle 184, 60\rangle\\&=184\;\vec{i} + 60\;\vec{j} \end{aligned}.

<h3>3.</h3>

\displaystyle \begin{aligned}7\;\vec{v} - 4\;\vec{w} &= 7\;\left(\begin{array}{c}-16\\6\end{array}\right) + (-4) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}-112 - 16\\42+20\end{array}\right)\\&= \left(\begin{array}{c}-128\\62\end{array}\right)= \langle -128, 62\rangle\\&=-128\;\vec{i} + 62\;\vec{j} \end{aligned}.

<h3>4.</h3>

\displaystyle \begin{aligned}\;\vec{u} - 5\;\vec{w} &= \left(\begin{array}{c}11\\12\end{array}\right) + (-5) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}11-20\\12+25\end{array}\right)\\&= \left(\begin{array}{c}-9\\37\end{array}\right)= \langle -9, 37\rangle\\&=-9\;\vec{i} + 37\;\vec{j} \end{aligned}.

7 0
3 years ago
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