The answer would be 2,569.
Answer:
a.) 0.7063
b.) 23
Step-by-step explanation:
a.)
Let X be an event in which at least 2 students have same birthday
Y be an event in which no student have same birthday.
Now,
P(X) + P(Y) = 1
⇒P(X) = 1 - P(Y)
as we know that,
Probability of no one has birthday on same day = P(Y)
⇒P(Y) =
where there are n people in a group
As given,
n = 30
⇒P(Y) =
= 0.2937
∴ we get
P(X) = 1 - 0.2937 = 0.7063
So,
The probability that at least two of them have their birthdays on the same day = 0.7063
b.)
Given, P(X) > 0.5
As
P(X) + P(Y) = 1
⇒P(Y) ≤ 0.5
As
P(Y) =
We use hit and trial method
If n = 1 , then
P(Y) =
= 1
0.5
If n = 5 , then
P(Y) =
= 0.97
0.5
If n = 10 , then
P(Y) =
= 0.88
0.5
If n = 15 , then
P(Y) =
= 0.75
0.5
If n = 20 , then
P(Y) =
= 0.588
0.5
If n = 22 , then
P(Y) =
= 0.52
0.5
If n = 23 , then
P(Y) =
= 0.49
0.5
∴ we get
Number of students should be in class in order to have this probability above 0.5 = 23
7 plus 7 equals 14. Add one to that and you have 15 which is the answer.
Answer:
.065 i think if im wrong im srry
Step-by-step explanation:
Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.