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3 years ago

Do the side lengths of 5, 6, and 8 form a Pythagorean triple?

1 answer:

5 0

The Pythagorean Theorem:
a^2 + b^2 = c^2

So we must check if:
5^2 + 6^2 = 8^2

25 + 36 ? 64
61 =/= 64

The side lengths 5, 6, and 8 do not form a Pythagorean triple.

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A radio telescope array is in an unpopulated desert region. The array covers a rectangular area that is one fourth square kilome

kramer

Answer:

3 km

Step-by-step explanation:

The area of a rectangle is given by the formula ...

A = LW

Filling in the given information, we can solve for the length.

1/4 = L·(1/12)

Multiplying by 12, we see that ...

3 = L

The array is 3 kilometers long.

3 0

3 years ago

The function a(1) =1/2I^2 describes the area of an isosceles right triangle with leg I. Make a table of values for I=1,2,3 and 4

prohojiy [21]

Functions can be represented using equations, graphs and tables.

The function is given as:

$a(l) = \frac 12 l^2$

When l = 1, we have:

$a(1) = \frac 12 \times 1^2$

$a(1) = 0.5$

When l = 2, we have:

$a(2) = \frac 12 \times 2^2$

$a(2) = 2.0$

When l = 3, we have:

$a(3) = \frac 12 \times 3^2$

$a(3) = 4.5$

When l = 4, we have:

$a(4) = \frac 12 \times 4^2$

$a(4) = 8.0$

Represent the above results as a table, we have:

1 0.5

2 2.0

3 4.5

4 8.0

Read more about tables and functions at:

brainly.com/question/13136492

8 0

2 years ago

(2x3z2)3 <br> ------------------ <br> x3y4z2 * (x-4z3)

Komok [63]

The rules of exponents tell you to add exponents in the numerator and subtract those in the denominator. A power of a power causes the exponent to be multiplied.

$\dfrac{(2x^{3}z^{2})^{3}}{x^{3}y^{4}z^2x^{-4}z^{3}}=2^{3}x^{(3\cdot3-3-(-4))}y^{-4}z^{(2\cdot3-2-3)}\\\\=\dfrac{8x^{10}z}{y^{4}}$