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Elodia [21]
3 years ago
6

The area of a rectangle is expressed as x4 - 9y2. What are the possible dimensions of the rectangle?

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

This is a stupid question.  The teacher who asked this needs to go back to school.

A = x⁴ - 9y²

That's going to be a number.  As long as it's positive we can choose any length for our rectangle L and we can compute the width by W=A/L.   So the correct answer is the dimensions are L by  (x⁴ - 9y²)/L.

They don't want the correct answer.  They want you to factor this expression.  We'll do it, but don't believe for a second this factoring somehow constrains the possible dimensions of some rectangle.

We use the difference of two squares, a²-b² = (a+b)(a-b)

A = x⁴ - 9y² = (x²)² - (3y)² = (x²+3y)(x²-3y)

Answer: x²+3y  by  x²-3y

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y = -20x + 100

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As per your requirement For Part B, the solution is

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lets use p1(0, 100), p2(1, 80)

now we will compute the slope:

m = \frac{(y2 - y1)}{(x2 - x1)}

m = \frac{(80 - 100)}{(1 - 0)}

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2 years ago
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vladimir2022 [97]

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3 years ago
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KonstantinChe [14]

Answer:

<T

Step-by-step explanation:

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dmitriy555 [2]

Answer:

The correct answer is b) 1100 adults and 1400 students.

Step-by-step explanation:

To find this, set up a system of equations in which x is the number of students who attend and y is the number of adults who attend.

First start by creating an equation for money made.

5x + 10y = 18,000

Now write an equation for the amount that attend.

x + y = 2,500

Now multiply the bottom equation by -5 and add the equations together.

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Since this is the number of adults, we can plug into an original equation to find the number of students.

x + y = 2,500

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5 0
3 years ago
Read 2 more answers
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