Answer:
In the 3rd quadrant
Step-by-step explanation:
Here, the given equation is,
x^2+y^2+px+6y-3=0
By copairing it with x^2+y^2+2gx+2fy+c=0, we get,
2g=p or, g=p/2
2f=6 or, f=3
c=-3
now the radius is,
r^2=g^2+f^2-c
or, 4^2=(p/2)^2 +3^2 -(-3)
or, 16= p^2/4 +9+3
or, 16-9-3=p^2/4
or p^2/4=4
or, p^2=4×4
or p^2=4^2
or p=4
therefore the rewuired value of p is 4.
Answer:

Step-by-step explanation:
Given two expressions ,
And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .
<u>Factorising</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>9</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Factorising</u><u> </u><u>3x</u><u>³</u><u> </u><u>+</u><u> </u><u>8</u><u>1</u><u> </u>
Hence we can see that (x+3) is common factor in both expressions.
<u>Hence</u><u> </u><u>the</u><u> </u><u>LCM</u><u> </u><u>is</u><u> </u><u>(</u><u> </u><u>x</u><u>+</u><u>3</u><u> </u><u>)</u><u> </u><u>.</u>