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3 years ago

10

Explain how to model the problem with algebra tiles and then write an algebraic expression that represents the situation. Amit f

ound eight more golf balls.

2 answers:

Dafna1 [17]3 years ago

8 0

Answer:

The variable, the number of golf balls, is modeled by an orange x tile. Finding 8 more balls is modeled by 8 orange + tiles. The expression that represents the situation is x + 8.

Step-by-step explanation:

Oksi-84 [34.3K]3 years ago

3 0

Answer:

The variable, the number of golf balls, is modeled by an orange x tile.

Finding 8 more golf balls is modeled by 8 orange + tiles.

The expression that represents the situation is x + 8.

Step-by-step explanation:

The variable, the number of golf balls, is modeled by an orange x tile. Finding 8 more balls is modeled by 8 orange + tiles. The expression that represents the situation is x + 8.

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Please help plz and explain

Liono4ka [1.6K]

Answer:

letter d or b

srry if wrong hope thiss helped

8 0

2 years ago

Please help! How do I solve this

Monica [59]

Answer:

(x,y) --> (-1, -3)

Step-by-step explanation:

Solve by elimination...

2x - 3y = 7

4x + y = -7 (times 3; so -3y and 3y cancel out)

2x - 3y = 7

12x + 3y = -21

2x = 7

12x = -21

add together...

14x = -14

x = -1

plug x into one of the original equations and solve for y...

-2 - 3y =7

-3y = 9

y = -3

8 0

2 years ago

How many sides does a regular polygon have with each exterior angle measures up to 30

ch4aika [34]

The answer would be 6 exteriors.

5 0

3 years ago

The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of

lora16 [44]

Answer:

The dimension of the sandbox is (2x+1) by (x - 3)

Step-by-step explanation:

It seems the complete question will be:

The area of sandbox in park is represented by 2X^2-5x-3 find the dimensions of the sandbox in terms of x.

Step-by-step explanation:

From the question, the given expression is 2X^2-5x-3. This can be rewritten as

$2x^{2} -5x-3$

If the area of the sandbox in park is represented by this expression, then the dimensions of the sandbox will be the product of the factors. To determine the factors, we will factorize the given quadratic expression.

Factorizing the expression $2x^{2} -5x-3$ , we get

$2x^{2} -6x+x-3$

$2x(x-3)+1(x-3)$

$(2x+1)(x-3)$

Hence, the dimension of the sandbox is (2x+1) by (x - 3)

6 0

3 years ago

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

2 years ago