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I am Lyosha [343]
3 years ago
9

The pastor divided the 3,000 circulars among 15 teenagers. How many circulars did each young person receive?

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0
Each young person received 200 circulars.

3,000/15= 200
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Question 1(Multiple Choice Worth 4 points)
Airida [17]
I think you mean x^2 - 7x + 8
This is a basic factoring problem:
What two numbers multiply to make 8 and add to make -7?
There are no two numbers that work!
Therefore, it is prime
4 0
2 years ago
Find the equivalent ratio for 32:__=12:24
Igoryamba
   
32 : 64 = 12 : 24

or


\displaystyle\\
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6 0
2 years ago
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I will give a thanks 5 stars and i will give you the brainliest Gwen mows 1/4 acre in 3/4 hours. what fraction is used to find t
Vinil7 [7]

Answer:

D

Step-by-step explanation:

4 0
3 years ago
I need the answer,Had to solve for homework and still working on it?
storchak [24]
They need to have common denomenators so change the fractions to 12/15 - 5/15 which is 7/15.
4 0
3 years ago
there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and
Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

4 0
2 years ago
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