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Ann [662]
3 years ago
12

Triangle XYZ with vertices X(0, 0), Y(0, –2), and Z(–2, –2) is rotated to create the image triangle X'(0, 0), Y'(2, 0), and Z'(2

, –2).
Mathematics
2 answers:
vodka [1.7K]3 years ago
5 0

Answer:


Step-by-step explanation:

Given that there is a triangle XYZ with vertices (0, 0), Y(0, –2), and Z(–2, –2)

This triangle is rotated to form image triangle X'(0, 0), Y'(2, 0), and Z'(2, –2).

We find that origin remains the same.

Hence point of rotation is about the origin

Now (0,-2) is transformed to (2,0)

This is possible if point is rotated about origin anticlockwise a degree of 90

Let us check new coordinate of Z by anticlockwise rotation of 90

We get Z'(2,-2)

Hence the transformation is rotation about origin anticlockwise by degree 90

Lady bird [3.3K]3 years ago
4 0

Answer:

The correct answwers are A and D

Step-by-step explanation:

On enge asswigment

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Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

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Where \|\vec u \| is the norm of \vec u, which is found by Pythagorean Theorem:

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The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

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