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vampirchik [111]
2 years ago
5

How do I find the length and the width?

Mathematics
1 answer:
Anastasy [175]2 years ago
4 0
The length is x+6, and the width is x. Hope this helps
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Jesse takes his dog and cat fort their annual vet visit.Jesse's dog weighs 23 pounds.The vet tells him his cats's weight is 5/8
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The cat weighs 14.375 pounds (or 230 ounces even).

Hope this helps!

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The table shows the total profits earned from magazine sales.
coldgirl [10]

Answer:

C. y= 14x+20

Step-by-step explanation:

By looking at the table, you can put in the x-values into all of the equations until you find the corresponding y-values that matches with the values in the table. For example: y= 14(2)+ 20, y=48. y= 14(20) +20, y=300. Hope this helped!

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(4x) to the power of -4​
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3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

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3 years ago
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Which statement best describes the polynomial
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B

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Standard form is written according to the highest exponent on the variable to the lowest. This expression has exponents that descend from 8 to 7 and to 1. B is the correct solution.

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