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Tpy6a [65]
3 years ago
5

Which conversion factors are used to convert 12 m/s to kilometers per minute?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer:

see the procedure

Step-by-step explanation:

we have

12\ \frac{m}{s}

Remember that

1\ km=1,000\ m

To convert m to km multiply by (1/1,000)

1\ min=60\ sec

To convert sec to min multiply by (1/60)

substitute

12\ (\frac{(1/1,000)}{(1/60)})=12(\frac{60}{1,000})=0.72\ \frac{km}{min}

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Answer!!!!! Help!!!
guajiro [1.7K]

Answer:

The answer is postulate

7 0
3 years ago
Ever since renata moved to her new home, she's been keeping track of the height of the tree outside her window. h(t)h(t)h, left
lilavasa [31]
It was 210 cm.

The function she used is h(t) = 210 + 33t.  This is a linear function, since it is of the form f(x) = mx+b.  In a linear function, we have the slope, m, which tells us how much the height increases per year, and the y-intercept, b, which tells us how tall it was when we began measuring.  Our m value would be 33 and our b would be 210, so the original height was 210.
4 0
3 years ago
Read 2 more answers
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
Which expression is equivalent to 7 (2x - 5)
zzz [600]

Answer:

14x-35

Step-by-step explanation:

Use distributive property so,

you multiply 2x and -5 by 7

2x*7=14x

-5*7=-35

3 0
3 years ago
Read 2 more answers
More than half of the students were excited about the project. In fact, were excited. If 10 students were not
alina1380 [7]

Answer:1/2 divided by 10

Step-by-step explanation:

8 0
3 years ago
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