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3 years ago

Brainiest for the smart cookie that solves this. It's hard, good luck!

Mathematics

1 answer:

marysya [2.9K]3 years ago

5 0

Answer:

672

Step-by-step explanation:

If there must be at least 4 people in each group, then the number of people in the group for tennis must be 4, 5, or 6.

There are

(10/k)=(10!)/(k!(10−k)!)

ways of choosing k people from a group of 10, and so there are

(10/4)+(10/5)+(10/6)=(10!)/(4!6!)+(10!)/(5!5!)+(10!)/(6!4!)

=2×(10×9×8×7)/(4×3×2×1)+(10×9×8×7×6)/(5×4×3×2×1)

=2×(10×3×1×7)/(1×1×1×1)+(1×3×2×7×6)/(1×1×1×1×1) =420+252=672

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∠ACB ≅ ∠AGB

Step-by-step explanation:

AAS Postulate is angle-angle-side, which means that both triangles are congruent if 2 angles and a side are congruent.

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3 years ago

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Answer:

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3 years ago

An ant crawls 10 centimeters down into an ant hole. It then crawls 2 centimeters up to the queen’s nest. How many centimeters do

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3 years ago

Formula for the surface area of a cylinder, SA = 2ar2 + 2arh. Solve for h.

MakcuM [25]

Answer:

$h=\frac{SA-2\pi r^2}{2\pi r}$

Step-by-step explanation:

The formula for the surface area of a cylinder is:

$SA=2\pi r^2+2\pi rh$

And we want to solve for the height h.

First, subtract $2\pi r^2$ from both sides. This yields:

$2\pi rh=SA-2\pi r^2$

Now, divide both sides by $2\pi r$ . This yields:

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And we're done!

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4 years ago

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2

Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find $P(4.2$

To find $P(4.2$ , we need to use z score formula:

When x = 4.2, we have:

$z = \frac{x-\mu}{\sigma}$

$=\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1$

When x = 5.1, we have:

$z = \frac{x-\mu}{\sigma}$

$=\frac{5.1-5.1}{0.9}=0$

Therefore, we have to find $P(-1$

Using the standard normal table, we have:

$P(-1$ = $P(z$

$=0.50-0.1587$

$=0.3413$ or 34.13%

= 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0

4 years ago