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Montano1993 [528]
3 years ago
8

Brainiest for the smart cookie that solves this. It's hard, good luck!

Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer:

672

Step-by-step explanation:

If there must be at least 4 people in each group, then the number of people in the group for tennis must be 4, 5, or 6.

There are

(10/k)=(10!)/(k!(10−k)!)

ways of choosing k people from a group of 10, and so there are

(10/4)+(10/5)+(10/6)=(10!)/(4!6!)+(10!)/(5!5!)+(10!)/(6!4!)

=2×(10×9×8×7)/(4×3×2×1)+(10×9×8×7×6)/(5×4×3×2×1)

=2×(10×3×1×7)/(1×1×1×1)+(1×3×2×7×6)/(1×1×1×1×1) =420+252=672

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3x ^ 3 - x ^ 2 Determine if the expression is polynomial or not . If it is a polynomial , state the type and degree of the polyn
kaheart [24]

Answer:

The given expression is a cubic polynomial with degree 3.

Step-by-step explanation:

We are given the following in the question:

3x^3-x^2

Polynomial:

  • A polynomial is an expression.
  • It  consisting of variables and coefficients.
  • The variables and coefficients involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.

Since, the given expression satisfies all the properties, it is a polynomial.

Degree of polynomial:

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The degree of given polynomial is 3.

Nature of polynomial:

It is a cubic polynomial.

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The cost to rent a car is $39.50 plus $0.25 per mile. If you only have $80, what is the greatest number of miles that you can dr
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Step-by-step explanation:

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3 years ago
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
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Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

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