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fomenos
3 years ago
12

Help please my teacher wont let me leave till im done with this question

Mathematics
1 answer:
ad-work [718]3 years ago
6 0

Answer:

To find the x intercept substitute 0 for y and solve for x. To find the y intercept substitute 0 for x and solve for y.

X intercept: (-2,0)

Y intercept: (0,5/2)

im not sure if you looking for the X and Y intercept for the second equation but if you are the

X intercept: (5/2,0)

Y intercept: (0,-5)

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This year ⅗ of the students in Fionna’s class identify as girls. Fionna notices that ⅔ of these girls wear braces. Only ½ of the
Tju [1.3M]

Answer:

³/5

Step-by-step explanation:

Total = 5 units

Girls = 3 units

~if ⅔ of the girls wear braces

= 2units of girs wear braces

Boys = 2 units

~if ½ of the boys wear braces

= 1unit of boys wear braces

Hence, 2units + 1unit =3 units of the class wears braces.

Total pupils = 5units

total that wear braces out of the whole class = 3/5

5 0
4 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
I accidentally fell asleep in math, I just need yes and no's please help me out!
snow_lady [41]

Answer:

No, yes, yes, yes, no, no, yes, no, yes, no, no, yes

Step-by-step explanation:

Explanation is in the comments by the way.

5 0
3 years ago
Andy is one fourth as old as his grandfather who is 76 years old write an equation to determine whether Andy is 19 or 22 years o
iren [92.7K]
76÷4= ; x=19, you divide 76 by 4 because if he is 1/4 then it would be a group of one of the 4's, thus saying ehen you divide 76 by 4, it equals 19, so he is 19 years old, you could also do 19×4 and 22×4 to see which equals 76.
7 0
3 years ago
7 freshmen, 8 sophomores, 8 juniors, and 10 seniors are eligible to be on a committee.
timurjin [86]

Answer:

There are 1,037,158,320  ways to choose a committee of 18 among 33 students.

There are 4,939,200 ways to choose 5 freshmen from 7, 6 sophomores from 8, 4 juniors from 8, and 3 seniors from 10.

Step-by-step explanation:

33!/18!15! = 1,037,158,320

7!/5!2! * 8!/6!2! * 8!/4!4! * 10!/7!3!

= 7*3 * 7*4 * 7*5*2 * 10*4*3 = 4,939,200

5 0
3 years ago
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