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OverLord2011 [107]
3 years ago
15

Which shape has 4 lines of symetry?

Mathematics
2 answers:
True [87]3 years ago
7 0
C because a rectangle has 4 lines of symmetry
sweet-ann [11.9K]3 years ago
7 0

Answer:

C. Rectangle

Step-by-step explanation:

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Answer:

C

Step-by-step explanation:

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9x^2-6x+8=0 what is the fifth step in solving this equation
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write the equation as a binomial

Step-by-step explanation:


8 0
3 years ago
Find the slope of the given line, if it is defined.
il63 [147K]

Answer:  A. The slope is -\dfrac{4}{3}.

Step-by-step explanation:

The slope of a line helps to specify the direction of the line.

The slope of a line that passes through (a,b) and (c,d) is given by :-

\text{Slope}=\dfrac{d-b}{c-a}

Then the slope of a line passes through origin i.e. (0,0) and (-9,12) is given by :-

\text{Slope}=\dfrac{12-0}{-9-0}\\\\\Rightarrow\ \text{Slope}=\dfrac{12}{-9}\\\\\Rightarrow\ \text{Slope}=-\dfrac{4}{3}

Hence, the slope is -\dfrac{4}{3}.

8 0
3 years ago
The numbers 1 through 15 are written on cards. One card is chosen at random. Event A is choosing a
lana [24]

Step-by-step explanation:

the probability is always the number of desired cases over the number of all possible cases.

in our situation we have 15 cards.

that is the total possible cases when a random card is chosen.

how many desired cases do we have ?

a number NOT a multiple of 5.

how many are there ?

it is easier to say how many numbers there are being a multiple of 5 : 5, 10, 15

so, 3 numbers out of the 15 are multiple of 5.

that means

15 - 3 = 12 numbers of the 15 are NOT multiples of 5.

so, the probability to draw a card that is not a multiple of 5 is

12/15 = 4/5 = 0.8

the information about event B and even numbers is irrelevant for the question.

6 0
2 years ago
Use the numbers 3 and 4 to make a fraction that is greater than 1 and a fraction less than 1. Explain how you made your fraction
Lana71 [14]

Answer:

4/3

Step-by-step explanation:

put one number on the top and one on the bottom. trial and error...

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3 years ago
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