We can use the fact that, for 
,
Notice that
![\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Cdfrac1%7B1-x%7D%5Cright%5D%3D%5Cdfrac1%7B%281-x%29%5E2%7D)
so that
![f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdisplaystyle%5Cfrac5%7B%281-x%29%5E2%7D%3D5%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Csum_%7Bn%3D0%7D%5E%5Cinfty%20x%5En%5Cright%5D)
By the ratio test, this series converges if
so the series has radius of convergence 
.
The sequence is increasing by the previous number multiplied by negative 3 (x -3). With this information, the correct answer would be A. -648, 1944, 5832
The 4 in and the 6 in are the same but the difference between the two triangles are 1.5
6:4 = 1.5
So if 12 = 1.5 (?)
The (?) = 8
Answer:
Option D: Absolute value function
Step-by-step explanation:
The absolute value of a number is the distance of the number from 0 to the left or right on the number line.
We are given the function;
f(x) = |2x³ - 3x| + 5
This function contains an absolute value symbol which is |2x³ - 3x|.
This function is thus illustrated by an an absolute value function because an absolute value function will be one that contains algebraic expressions within absolute value symbols.
There is no single solution but there is a group of solutions also known as the interval.
This can be written with an interval.
Hope this helps.
r3t40
