Hello from MrBillDoesMath!
Answer:
Discussion:
I stared at the numbers 19, 29, 39, 49, 59, 69,... for a second and noticed that adding 10 to any number gives the next number to the right. For example,
19 + 10 = 29
29 + 10 = 39
39 + 10 = 49
etc.....
A recursive formula would be:
a(0) = 19
a(n+1) = a(n) + 10 if n >= 0
Regards,
MrB
<h3>Answer: </h3>
about 1.768 seconds
<h3>Explanation:</h3>
Since the phone is <em>dropped</em>, the first equation applies. The final height is assumed to be zero, so we have ...
... h(t) = 0 = -16t² +50
... 16t² = 50 . . . . . . . . add 16t²
... t² = 50/16 . . . . . . . . divide by 16
... t = √3.125 . . . . . . . take the square root
... t ≈ 1.768 . . . . . . . . round to milliseconds
Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Answer:
Given that:
where
L(t) represents the length of each day(in minutes) and t represents the number of days.
Substitute the value of L(t) = 750 minutes we get;
Subtract 728 from both sides we get;
Divide both sides by 52 we get;
or
Simplify:
or
Simplify:
days
Therefore, the first day after the spring equinox that the day length is 750 minutes, is 25 days
I would say B .
They are not like terms because they are not all the same
