2cos(x) - 4sin(x) = 3
use identity [cos(x)]^2 +[ sin(x)]^2 = 1 => cos(x) = √[1 - (sin(x))^2]
2√[1 - (sin(x))^2] - 4 sin(x) = 3
2√[1 - (sin(x))^2] = 3 + 4 sin(x)
square both sides
4[1 - (sin(x))^2] = 9 + 24 sin(x) + 16 (sin(x))^2
expand, reagrup and add like terms
4 - 4[sin(x)]^2 = 9 + 24sin(x) + 16sin^2(x)
20[sin(x)]^2 + 24sin(x) +5 = 0
use quadratic formula and you get sin(x) = -0.93166 and sin(x) = -0.26834
Now use the inverse functions to find x:
arcsin(-0.93166) = 76.33 degrees
arcsin(-0.26834) = 17.30 degrees
For this case, the first thing you should know is that the opposite sides of the parallelogram are the same.
Therefore, we have the following equations:

From equation 1 we have:


From equation 2 we have:


Answer:
the value of the variables are:

Answer:
The distance is 8 cm
Step-by-step explanation:
The chord and the diameter form one leg and the hypotenuse of a right triangle. The other leg, BD, has length ...
BD² +AB² = AD²
BD² = AD² -AB² = 34² -30² = 256
BD = √256 = 16
The segment from the center of the circle to the midpoint of the chord is the midline of triangle ABD, so is half the length of BD.
distance from AB to the center = 16/2 = 8 . . . cm
<span>1 and 2/3 time 1 and 1/3 is 2.22222222222 which rounds to 2.</span>