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prisoha [69]
3 years ago
15

27 students in all 4:5 packed lunch. how many students packed lunch

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0
\bf \stackrel{total}{27}\qquad 4:5\qquad \cfrac{4}{5}\implies \cfrac{4\cdot \frac{27}{4+5}}{5\cdot \frac{27}{4+5}}\implies \cfrac{4\cdot 3}{5\cdot 3}\implies \cfrac{\stackrel{packed~lunch}{12}}{\stackrel{did~not~pack~lunch}{15}}
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3 years ago
3. Solve the following application of a system of linear equations.
zhuklara [117]

Answer:

Equations:

y =  14 + 9 x --- Cindy

y = 10 x --- Ruben

Solution to equation:

Time they have the same amount: 14 minutes

Number of cards they have at that time: 140 flashcards

Step-by-step explanation:

Solving (a): Variables and what they represent

The variables to use are x and y

Where x represent the minutes and y represents the number of flashcards in x minutes

Solving (b): System of linear equation

Cindy:

Existing\ Flashcards = 14

Additional = 9 per minute

Total number of flashcards (y) in x minutes is:

y =  Existing\ Flashcards + Additional * x

y =  14 + 9 * x

y =  14 + 9 x

Ruben:

Rate = 10 per minute

Total number of flashcards (y) in x minutes is:

y = Rate * x

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Solution to Equations:

Time they have the same amount.

To do this, we equate both expressions

i.e.

10x = 14 + 9x

Collect Like Terms

10x - 9x = 14

x = 14

Number of cards they have at that time.

Here, we simply substitute 14 for x in any of the equations.

y = 10 x

y = 10 * 14

y = 140

or

y =  14 + 9 x

y = 14 + 9 * 14

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Step-by-step explanation:

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