Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:
6x
Step-by-step explanation:
Area of triangle = l x w => 2x x 3x = 6x
Answer:
15x - y = - 6.....15x + 6 = y...so we sub in 15x + 6 in for y on the other equation
5x - 3y = -13
5x - 3(15x + 6) = -13 <== the new equation
Step-by-step explanation:
Answer:
$103968.11
Step-by-step explanation:
Given information:
Principal amount = $240,000
Rate of interest = 1.2% = 0.012
Number of years = 30
Number of times in an year = 24
Formula for amount:
where
P is principal, r is rate of interest, t is number of years, n is number of times interest compounded in a year.
Now,
Hence, the interest is $103968.11.
