Given:
Sum of arithmetic sequence is 21.
Product of arithmetic sequence is 315.
I did a manual computation. Arithmetic sequence means that there is a constant difference between the two consecutive numbers.
x + (x+2) + (x + 2 + 2) = 21
3x + 6 = 21
3x = 21 - 6
3x = 15
x = 15/3
x = 5 1st number
x + 2 = 5 + 2 = 7 2nd number
x + 2 + 2 = 5 + 2 + 2 = 9 3rd number.
5 + 7 + 9 = 21
5 x 7 x 9 = 315
Answer:
Step-by-step explanation:
Remark
- x is opposite the 90 degree angle. It is the hypotenuse.
- 13 makes up the 57 degree angle. It is the side adjacent.
- The adjacent side and the hypotenuse define the cos(theta).
Formula
cos(theta) = adjacent side / hypotenuse
Givens
Theta = 57 degrees
Hypotenuse = x
Side adjacent = 13
Solution
- Cos(57) = 13 / x Multiply both sides by x
- x*cos(57) = 13 Divide by cos(theta)
- x = 13/cos(57)
- x = 13 / cos(57)
- cos(57) = 0.5446
- x = 13/ 0.5446
- x = 23.87
Answer:
C
Step-by-step explanation:
please mark brainliest
Answer:
Step-by-step explanation:
Given
![6\ [\ ]\ (\ 3\ [\ ]\ 1\ )\ [\ ]\ 5\ [\ ]\ 1\ =\ 17](https://tex.z-dn.net/?f=6%5C%20%5B%5C%20%5D%5C%20%28%5C%203%5C%20%5B%5C%20%5D%5C%201%5C%20%29%5C%20%5B%5C%20%5D%5C%205%5C%20%5B%5C%20%5D%5C%201%5C%20%3D%5C%2017)
Required
Fill in the box with +,-, x, and ⌯ (once each)
This question is solved using trial by error approach.
After some tests, the solution that matches the equation is:
Nick has tennis practice every sixth day = 6
Mark has tennis practice every 4th day = 4
They both had tennis practice on = 31st July
We have to find when will be the next time that they both have practice on the same day?
For this, we will find the LCM of 4 and 6
So, LCM of 4 and 6 is 12.
So, it will be 12 days after 31st July, that they will practice on the same day.
So it is 12th August.
