Answer:
y = root under 24 (evaluate it if necessary)
or y = 2 root 6
Step-by-step explanation:
Let the reference angle be x
for the triangle in left,
b = 6-4 = 2
Now,
taking x as refrence angle,
cosx = b/h
or, cosx = 2/h
again,
for the bigger triangle,
taking x as reference angle,
cosx = b/h
or, cosx = b/6
As we can see base of bigger triangle is equal to hypotenuse of triangle at the left,
Let's suppose its a
so, cosx = a/6 = 2/a
now,
a/6 = 2/a
or, a² = 12
now,
for bigger triangle, using pythagoras theorem,
h² = p²+b²
or, 6² = y² + a²
or, 36 = y² + 12
or, y² = 24
so, y = root under 24
Answer:
see the attachment for a table
Step-by-step explanation:
A. The table is shown in the attachment. The solution to h(t) = g(t) is at a value of t that lies between 6 and 7. At t=6, h(t) > g(t). At t=7, h(t) < g(t). Since both functions are continuous, they must have equal values somewhere between t=6 and t=7. (Intermediate value theorem.)
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B. The solution means the cannon balls will have the same height at a value of t between 6 and 7.
Answer:
Let the smaller number be x
Then the sum is
(6 + 2x) + x = 27
We now find for x
2x + x + 6 = 27
3x + 6 = 27
3x = 27-6
3x = 21
x = 21/3
x = 7
Therefore the smaller number is 7
The larger number is (2×7) + 6 = 20