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Grace [21]
2 years ago
13

A $\textit{palindrome}$ is a positive integer which reads the same forward and backward, like $12321$ or $4884$. How many $4$-di

git palindromes are there
Mathematics
1 answer:
Norma-Jean [14]2 years ago
4 0

There are 90 4-digit palindromes

<h3>What are palindromes?</h3>

Palindromes are numbers whose reverse is the same as the original number

<h3>How to determine the count of 4-digit palindromes</h3>

Since the digit is 4, then

  • The first digit of the palindrome can be any of 1 to 9 (i.e. 9 digits)
  • The second digit can be any of 0 - 9 (i.e. 10 digits)
  • The third digit must be the second digit (i.e. 1 digit)
  • The last digit must be the first digit (i.e. 1 digit)

So, the total number of digits is:

n =9 * 10 * 1 * 1

Evaluate the product

n =90

Hence, there are 90 4-digit palindromes.

Read more about numbers at:

brainly.com/question/251701

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Answer:

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Step-by-step explanation:

1) find the distance of the points

\sqrt{(x2-x1)^2 + (y2 -y1)^2}

AB = \sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}

BC = |7-4| = 3

CD = \sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}

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2) equation of the line that passes threw BC

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3) equation of the line that passes threw AD

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conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

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