Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and
.
To find:
The
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]


In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
The base angles of an isosceles triangle are congruent. So,
[Base angles of an isosceles triangle]


Using the angle sum property in triangle AOB, we get





Hence, the measure of angle AOB is 120 degrees.
Answer:
y = x + 1
Step-by-step explanation:
Y=k/x is inverse
y=2
x=8
2=k/8
times 8
16=k
the equation is
y=16/x
second
y=k/x
-3=k/1
-3=k
the equation is y=-3/x
they are
for y=2, x=8 it is y=16/x
and for y-3, x=1 it is y=-3/x
Answer:
The only one
Step-by-step explanation:
The one that is shown has a negative b^2-4ac value.
We know this because the function has no real roots -> that means that they must be complex, which can only occur if b^2-4ac < 0