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Anestetic [448]
3 years ago
13

Paleontology is a subspecialty of

Physics
1 answer:
faltersainse [42]3 years ago
8 0
It's a subsection of Geology and Biology
You might be interested in
A forklift lifts 5 boxes from the ground to a height of 2 meters (m). The boxes push down with a force of 1000 newtons (N). How
Nata [24]
Hello!

Answer:

2000 J

Explanation

Work equation is expressed as:

W=F.d.Cos \alpha

Where:

F: Applied force
d: traveled distance
α: Angle between the direction of the force and the direction of the movement. (in this case, both of the direction are the same, so the angle is 0°)

By substituting:

F=1000N.2m.Cos(0)=2000N.m=2000 J

Have a nice day!
8 0
4 years ago
If a current is two amps and the resistance is 3 ohms, how much voltage was needed?
Hunter-Best [27]

Answer:

6 V

Explanation:

We can solve the problem by using Ohm's law:

V=RI

where

V is the voltage in the circuit

R is the resistance

I is the current

In this problem, we know the current, I=2 A, and the resistance, R=3 \Omega, therefore we can find the voltage in the circuit:

V=RI=(3 \Omega )(2 A)=6 V

7 0
3 years ago
What is the electric force (with direction) on an electron in a uniform electric field of strength 3400 N/C that points due east
wlad13 [49]

Answer:

  • So, the force its \ 5.4468 \ 10 ^{-16} N to the west.

Explanation:

The force \vec{F} on a charge q made by an electric field \vec{E} its

\vec{F} = q \vec{E}

The electric charge of the electron its

q \ = \ - \ 1.602 \ 10 ^{-19} \ C.

Taking the unit vector \hat{i} pointing towards the east, the electric field will be:

\vec{E}= 3400 \ \frac{N}{C} \ \hat{i}.

So, the force will be:

\vec{F} =  \ - \ 1.602 \ 10 ^{-19} \ C \ * \ 3400 \ \frac{N}{C} \ \hat{i}

\vec{F} =  \ - \ 5446.8 \ 10 ^{-19} \ N \ \hat{i}

\vec{F} =  \ - \ 5.4468 \ 10 ^{-16} \ N \ \hat{i}

\vec{F} =  \ - \ 5.4468 \ 10 ^{-16} \ N \ \hat{i}

\vec{F} =  \ - \ 5.4468 \ 10 ^{-16} \ N \ \hat{i}

So, the force its \ 5.4468 \ 10 ^{-16} N to the west.

5 0
3 years ago
At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant
Blizzard [7]
(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then 
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

--------------------

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0
3 years ago
Climate Change
notsponge [240]

Answer:

hope it's helpful please Like me

8 0
3 years ago
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