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yKpoI14uk [10]
4 years ago
11

A _________ is an FDM device that splits the physical circuit into three logical circuits (phone, upstream data, downstream data

). DSL modem Cable modem Wireless router V.44 modem Serial modem
Physics
1 answer:
son4ous [18]4 years ago
4 0

Answer:

DSL modem

Explanation:

Digital Subscriber Line (DSL) technology is a modem technology that uses existing twisted-pair telephone lines to transport high-bandwidth data, such as multimedia and video, to service subscribers.

Hence, we can also say that a DSL Modem is an FDM (frequency division multiplexing) device that splits the physical circuit into three logical circuits such as phone, upstream data, and downstream data.

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Definition of mass<br> definition of density<br> definition of physical properties
butalik [34]

Answer:

Mass of a body is define as the total quantity of matter contained in it .

Density is the mass per unit volume in any object .

A physical properties is an any property that is measurable , whose value describe a state of a physical system

6 0
3 years ago
A basketball with a mass of 0.5 kilograms is accelerated at 2 meters per second". The nat force acting on the mass is _____
Elanso [62]
Should be d, 1N
hope this helps
7 0
3 years ago
Which wave causes the medium to vibrate only in a direction parallel to the wave’s motion?
andreyandreev [35.5K]
When the vibration is in a direction parallel to wave's motion that is a Longitudinal wave  (C).

But When the vibration is in a direction perpendicular to wave's motion then it is Transverse wave.

6 0
4 years ago
Read 2 more answers
If T, = 40 N, find T, and the mass of the weight (W).
seraphim [82]

Answer:4kg

Explanation:

acceleration due to gravity(g)=10m/s^2

Weight(w)=40N

Weight=mass x g

40=mass x 10

Divide both sides by 10

Mass =40/10

Mass=4kg

5 0
4 years ago
A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m an
Ber [7]

Complete Question

A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 7.10 m/s. What is the x-coordinate of the object when t = 10.0 s?

Answer:

The position of the object at t = 10s is  X  =  38.3 \  m

Explanation:

From the question we are told that

The acceleration along the x axis is  a_{x}t  =  -(0.0320\ m/s^3)(15.0 s- t)- (0.0320\ m/s^3)

  The position of the object at t = 0 is  x = -14.0 m

  The velocity at t = 0 s is  v_{0}x = 7.10 m/s

Generally from the equation for acceleration along x axis we have that

     a_x = \frac{dV_{x}}{dt}  = -0.032 (15- t)

=>   \int\limits  {dV_{x}} \, = \int\limits  {-0.032(15- t)} \, dt

=>   V_{x} = -0.032 [15t - \frac{t^2 }{2} ]+ K_1

At  t =0  s   and  v_{0}x = 7.10 m/s

=>   7.10  = -0.032 [15(0) - \frac{(0)^2 }{2} ]+ K_1

=>   K_1 = 7.10      

So  

      \frac{dX}{dt}  = -0.032 [15t - \frac{t^2 }{2} ]+ K_1

=>  \int\limits dX  = \int\limits [-0.032 [15t - \frac{t^2 }{2} ]+ K_1] }{dt}

=>  X  =  -0.032 [ 15\frac{t^2}{2}  - \frac{t^3 }{6} ]+ K_1t +K_2

At  t =0  s   and   x = -14.0 m

  -14  =  -0.032 [ 15\frac{0^2}{2}  - \frac{0^3 }{6} ]+ K_1(0) +K_2

=>   K_2 = -14

So

     X  =  -0.032 [ 15\frac{t^2}{2}  - \frac{t^3 }{6} ]+ 7.10 t -14

At  t = 10.0 s

      X  =  -0.032 [ 15\frac{10^2}{2}  - \frac{10^3 }{6} ]+ 7.10 (10) -14

=>   X  =  38.3 \  m

             

     

5 0
3 years ago
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