Answer:
-5/6x+2
Step-by-step explanation:
hope that helps
Answer:
They both have area 4
Step-by-step explanation:
Area of the square:
Area of the triangle:
Using the left-side of the triangle as the base, and the height from the left-side to the bottom-right corner:
We know the length of the diagonal is 
as we are using a centimetre grid, so we can create an isosceles triangle with side lengths 1 and our unknown length, we can then use Pythagorean Theorem to work out our unknown side length.
I am thinking of a rectangle that has the two sides parallel to one another. Set the two functions equal to one another, so
9x-14=7x+4
After a bunch of algebra and math magic, 2x=18 => x=9
So if you just insert 9 into both equations, both will end up with a value of 67, so it ends up looking like a right triangle. Don't do that. Instead, to find the rectangle widths, use 9x-4 (+10 added to intercept) instead, while keeping 7x+4, so that the intercepts match.
LN) 9x-4 = 9(9)-4 = 81-4 = 77
MP) 7(9)+4 = 63+4 = 67
*If you are also looking for the diagonals, use Pythagorean Theorem 77^2+67^2=(hypotenuse)^2*
Answer:
12√3 inches or 20.785 inches.
Step-by-step explanation:
A regular hexagon can be defined as a polygon with 6 sides.
The formula for the perimeter of a regular hexagon =
6 × the length of the sides of the hexagon.
From the above question, we are told that there is an inscribed circle I'm the hexagon with a diameter of 4√3 inches long
Step 1
Find the radius of the circle
Radius of the circle = 4√3/2 = 2√3 inches
Step 2
The radius of the inscribed circle = Length of one of the sides of a regular hexagon.
Hence, the perimeter of the regular hexagon = 6 × 2√3
= 12√3 inches
= 20.784609691 inches.
Approximately 20.785 inches
