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Nikolay [14]
3 years ago
15

What happens when sediments are buried ,compacted,and cemented together

Physics
2 answers:
love history [14]3 years ago
7 0
They create sedimentary rock
Artemon [7]3 years ago
5 0

Answer:

they create sedimentary rock

Explanation:

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Compare the momentum of a 6,300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s. your answer
bogdanovich [222]
<span>First sum applied the Newton's second law motion: F = ma Force = mass* acceleration This motion define force as the product of mass times Acceleration (vs.Velocity). Since acceleration is the change in velocity divided by time, force=(mass*velocity)/time such that, (mass*velocity)/time=momentum/time Therefore we get mass*velocity=momentum Momentum=mass*velocity Elephant mass=6300 kg; velocity=0.11 m/s Momentum=6300*0.11 P=693 kg (m/s) Dolphin mass=50 kg; velocity=10.4 m/s Momentum=50*10.4 P=520 kg (m/s) The elephant has more momentum(P) because it is large.</span>
5 0
3 years ago
The internal pressure on a bottle of soda is 5550 torr. the bottle cap is designed to withstand a pressure of 7.2 atm. (a) calcu
Mademuasel [1]

This is a conversion problem. 760 Torr is equal to 1 atmosphere. so we can can solve now. 5,550torr*(1atmosphere/760torr)=7.3atmospheres. since the two torrs cancel out with cross multiplication we are left in atmosphere units.

6 0
3 years ago
Read 2 more answers
Determine the velocity required for a moving object 2.00 x 10^4 m above the surface of Mars to escape from Mars's gravity. The m
Ket [755]

Answer:

Therefore the escape velocity from Mar's gravity is 15.88 \times 10^4 m/s.

Explanation:

Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.

V_{escape}=\sqrt{\frac{2GM}{R}}

V_{escape}= Escape velocity

G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²

M= mass of Mars = 6.42×10²³ kg

R = Radius of the Mars = 3.40×10³m

The escape velocity does not depend on the velocity of a object.

V_{escape}=\sqrt{\frac{2\times6.673\times 10^{-11}\times 6.42\times 10^{23}}{3.40\times10^3}}

           =15.88 \times 10^4 m/s

Therefore the escape velocity from Mar's gravity is 15.88 \times 10^4 m/s.

           

3 0
3 years ago
If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.
Schach [20]

Answer:

The magnitude of each charge is 2.82\times10^{-6}\ C

Explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

F=\dfrac{kq^2}{r^2}

Where, q = charge

r = separation

Put the value into the formula

20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}

q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}

q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}

q=2.82\times10^{-6}\ C

Hence, The magnitude of each charge is 2.82\times10^{-6}\ C

6 0
3 years ago
Solving for acceleration,mass and net force
Dvinal [7]
The formulas are-

a=f/m
f=ma
m=f/a
5 0
3 years ago
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