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Leni [432]
3 years ago
5

A 2 Ω resistor, an 8 Ω resistor, and a 12 Ω

Physics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:R=1,4Ω

Explanation:

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A 58.1 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 48.3 kg boy stands at one end of the board.
VLD [36.1K]

Answer:

V = 1.41 m /s

Explanation:

Movement in both wood board and boy is created by internal forces . No horizontal external force acts on them . So conservation of momentum will apply on both of them for movement in horizontal direction.

Mass of wood board x velocity = mass of boy x velocity

58.1 x V = 48.3 x 1.69

V = 1.41 m /s

4 0
4 years ago
Can someone help me :)
Mamont248 [21]

Answer:

mass= 60kg

velocity= 10m/s

momentum = mass × velocity

p=m×v

p= 60×10

p= 600kgm/s

5 0
3 years ago
It takes 50.0 J to push a large box 4.00 m across a floor. Assuming the push is in the same direction as the move, what is the m
Blababa [14]
<h3><u>Answer;</u></h3>

12.5 Newtons

<h3><u>Explanation;</u></h3>

Work done is defined as the product of force and distance covered or moved. It is measured in joules.

Work done = Force × distance

Therefore; making force the subject;

Force = work done/distance

         = 50.0 J/ 4.00 m

         =<u> 12.5 Newtons.</u>

8 0
3 years ago
What is the difference between the purines and the pyrimidines?
Natali [406]
They both are types or categories of nitrogen containing bases present in nuclei acids of DNA and RNA.

Purines are 2 Ring or Carbon Ring, Nitrogen containing bases. That consist of these 2 rings next placed next to each other. These examples include - Adenine and Guanine.

Pyrimidines are 1 or single Ring Nitrogen containing structures. There are 3 nitrogenous bases that are categorized as pyrimidines. Cytosine, Thymine, and Uracil.
3 0
3 years ago
Two very large parallel metal plates, separated by 0.20 m, are connected across a 12-V source of potential. An electron is relea
Semmy [17]

Answer:

{\rm K} = 2.4\times 10^{-19}~J

Explanation:

The electric field inside a parallel plate capacitor is

E = \frac{Q}{2\epsilon_0 A}

where A is the area of one of the plates, and Q is the charge on the capacitor.

The electric force on the electron is

F = qE = \frac{qQ}{2\epsilon_0 A}

where q is the charge of the electron.

By definition the capacitance of the capacitor is given by

C = \epsilon_0\frac{A}{d} = \frac{Q}{V}\\\frac{Q}{\epsilon_0 A} = \frac{V}{d} = \frac{12}{0.20} = 60

Plugging this identity into the force equation above gives

F = \frac{qQ}{2\epsilon_0 A} = \frac{q}{2}(\frac{Q}{\epsilon_0 A}) = \frac{q}{2}60 = 30q

The work done by this force is equal to change in kinetic energy.

W = Fx = (30q)(0.05) = 1.5q = K

The charge of the electron is 1.6 \times 10^{-19}

Therefore, the kinetic energy is 2.4\times 10^{-19}

8 0
4 years ago
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