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Verizon [17]
3 years ago
14

You tie a string to the ceiling and attach a weight to the end. You hold the weight next to your face but not touching it and th

en let go. The weight swings down and away from you and then starts swinging back toward you. If you do not move, will it hit you?
Physics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

Depends on how long the string is, how heavy the weight, and how high you let go of it.

But it will most likely hit you :)

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3 years ago
10. If the mass of the Earth is... increased by a factor of 2, then the Fgrav is ______________ by a factor of _______. ... incr
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Answer:

If the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.

If the mass of the earth is increased by a factor of 3, then Fgrav is increased by a factor of 3.

If the mass of the earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4

Explanation:

In order to solve this question, we must take into account that the force of gravity is given by the following formula:

F_{g0}=G \frac{mM_{E0}}{r^{2}}

So if the mass of the earth is increased by a factor of 2, this means that:

M_{Ef}=2M_{E0}

so:

F_{gf}=G \frac{2mM_{E0}}{r^{2}}

Therefore:

\frac{F_{gf}}{F_{g0}}=\frac{G \frac{2mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}

When simplifying we end up with:

\frac{F_{gf}}{F_{g0}}=2

so if the mass of the Earth is increased by a factor of 2, then the Fgrav is increased by a factor of 2.

If the mass of the earth is increased by a factor of 3

So if the mass of the earth is increased by a factor of 2, this means that:

M_{Ef}=3M_{E0}

so:

F_{gf}=G \frac{3mM_{E0}}{r^{2}}

Therefore:

\frac{F_{gf}}{F_{g0}}=\frac{G \frac{3mM_{E0}}{r^{2}}}{G \frac{mM_{E0}}{r^{2}}}

When simplifying we end up with:

\frac{F_{gf}}{F_{g0}}=3

so if the mass of the Earth is increased by a factor of 3, then the Fgrav is increased by a factor of 3.

If the mass of the earth is decreased by a factor of 4

So if the mass of the earth is decreased by a factor of 4, this means that:

M_{Ef}=\frac{M_{E0}}{4}

so:

F_{gf}=G \frac{mM_{E0}}{4r^{2}}

Therefore:

\frac{F_{gf}}{F_{g0}}=\frac{G \frac{mM_{E0}}{4r^{2}}}{G \frac{mM_{E0}}{r^{2}}}

When simplifying we end up with:

\frac{F_{gf}}{F_{g0}}=\frac{1}{4}

so if the mass of the Earth is decreased by a factor of 4, then the Fgrav is decreased by a factor of 4.

4 0
3 years ago
The activation energy for the isomerization reaction of CH3NC in Problem 14 is 161 kJ mol 1, and the reaction rate constant at 6
astraxan [27]

Answer:

Explanation:

Below is an attachment containing the solution to the question.

5 0
3 years ago
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