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3 years ago

9

What would you expect the nominal rate of interest to be if the real rate is 4.4 percent and the expected inflation rate is 7.5

percent?

1 answer:

ANTONII [103]3 years ago

5 0

Answer:

Nominal Interest rate=11.9%

Step-by-step explanations:

The Fisher effect is a theory propounded by an economist named Irving Fisher.

Fisher's equation shows the relationship between real Interest rate, expected inflation rate and nominal Interest rate.

It can be calculated by subtracting the expected inflation rate from the nominal Interest rate to give the real Interest rate.

Real Interest rate= nominal Interest rate - expected inflation rate

Given,

Real Interest rate= 4.4%=0.044

Expected inflation rate=7.5%=0.075

Nominal Interest rate=?

Therefore,

Real Interest rate=nominal Interest rate - expected inflation rate

Nominal Interest rate=Real Interest rate+expected inflation rate

Nominal Interest rate=0.044+0.075

Nominal Interest rate=0.119

Nominal Interest rate=11.9%

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3(4x−2)=2(5x+3) what is the answer pls asap

Paha777 [63]

Answer:

6

Step-by-step explanation:

1. get rid of parentheses: 12x -6 = 10x +6

2. group like terns together: 12x-10x = 6+6

3. simplify: 2x = 12

4. divide both sides by 2: x=6

7 0

3 years ago

Read 2 more answers

3x+2y=23<br> 1/2x-4=y<br><br> What should I do for this one...? I dont really understand

Hitman42 [59]

Since you have y alone on one side of the equation......

Use substitution and plug in 1/2x-4 for y in the other equation.

$3x+2(1/2x-4)=23\\$

Distribute

$3x+x-8=23$

Combine like terms

$4x-8=23$

Add 8 to both sides

$4x=31$

Divide by 4

and $x=31/4$

Plug this value in for x

$31/4*1/2-4=y$

Simplify

$31/8-4=y$

Multiply everything by 8 and simplify

$31-32=8y\\-1=8y$

Divide.....

$y=-1/8$

Your answers are:

$y=-1/8\\x=31/4$

8 0

3 years ago

Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound

cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0$

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

$p_1=X_1/n_1=188/244=0.77049$

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

$p_2=X_2/n_2=197/247=0.79757$

The difference between proportions is (p1-p2)=-0.02708.

$p_d=p_1-p_2=0.77049-0.79757=-0.02708$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76$

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(t$

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0

3 years ago

Name the sets of numbers to which -10 belongs

lesya [120]

1 , 2, 3, -1, -2, -3

6 0

3 years ago

Find the value of each expression. Show your work.

Verdich [7]

Answer:

$A) (1.2)^{2} = 1.44$

$B)2^ 3+17-(3\times 4) = 13$

$C)\frac{(9)^2}{(3)^3} = 3$

Step-by-step explanation:

Here, the given expressions are:

A) $(1.2)^{2}$

Solving this, we get

$(1.2)^{2} = 1.2 \times 1.2 = 1.44$

⇒ $(1.2)^{2} = 1.44$

B) $2^ 3+17-(3\times 4)$

Now, solving this, we get

$2^ 3+17-(3\times 4) = (2 \times 2 \times2) + (17 -12)\\=8 + 5 = 13$

⇒ $2^ 3+17-(3\times 4) = 13$

C) $\frac{(9)^2}{(3)^3}$

Simplifying this, we get

$\frac{(9)^2}{(3)^3} = \frac{(9\times9)}{(3 \times 3\times3)} = 3$

⇒ $\frac{(9)^2}{(3)^3} = 3$

4 0

3 years ago