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zloy xaker [14]
3 years ago
11

How do I figure out the third measure of a triangle

Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0
If you add all three interior angle measures together in a triangle it will always equal 180°.. To find a third angle you will subtract the sum of the two given angles from 180°.
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Eleven less than three times a number is 85. Find the number.<br> w=
zubka84 [21]

Answer:

the answer would be 32.

Step-by-step explanation:

add 11 to 85, then divide the number you get (96) by 3.

7 0
3 years ago
(\tan ^(2)\theta \cos ^(2)\theta -1)/(1+\cos (2\theta ))=
Vitek1552 [10]

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall that

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:

(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall the double angle identity for cosine,

cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

so the 1 in the denominator also vanishes:

(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))

Recall the Pythagorean identity,

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

which means

sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):

-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))

Cancel the cos²(<em>θ</em>) terms to end up with

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2

7 0
3 years ago
Which of the following are ordered pairs for the equation y = 1/8x + 11
Anna11 [10]

Answer:

(0, 11) is a solution.

(8, 12)  is a solution.

(16, 13) is a solution

(1, 89/8)  

(2,  45/4)

Step-by-step explanation:

y = 1/8x + 11

for this equation....

y = (1/8) x + 11

let x = 0  get

y = 0 + 11 = 11

(0, 11) is a solution.

(8, 12)  is a solution.

(16, 13) is a solution

(1, 89/8)   because    y = 1/8 + 11 = 1/8 + 88/8 = 89/8

(2,  45/4)

3 0
3 years ago
I need help with this and fast if possible
11Alexandr11 [23.1K]

Answer:

<em>The answer is Hence Proved</em>

Step-by-step explanation:

       Given that CB║ED ,  CB ≅ ED

       To prove Δ CBF ≅ Δ EDF

  •       CB ≅ ED   ( Given )

        This means that the length of CB is equal to ED

        As CB║ED The following conditions satisfies when a transversal cut

        two parallel lines

  •    ∠ EDF = ∠ FBC   ( Alternate interior points )
  •    ∠ DEF = ∠ FCB   ( Alternate interior points )

       ∴ Δ CBF ≅ Δ EDF    ( By ASA criterion)

        The Δ CBF is congruent to Δ EDF By ASA criterion .

    <em>    Hence proved </em>

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3 years ago
$80 at 12%for 2years
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8 0
3 years ago
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