Answer:
we know that
the equation of the circle is of the form
(x-h)^2+(y-k)^2=r^2
where
(h,k) is the center of the circle
r is the radius of the circle
in this problem we have
(x+5)^2+(y-k)^2=r^2
so
the center is the point (-5,3)
the radius is 4 units
therefore
the answer is
The radius of the circle is equal to 4 units
Use Pythagorean theorem
a^2 + b^2 = c^2
12^2 + 35^2 = c^2
144 + 1225 = c^2
1369 = c^2
Sqrt 1369 = c
37 = c
Answer:
Yes
Step-by-step explanation:
You can conclude that ΔGHI is congruent to ΔKJI, because you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K).
We also know that we have two congruent sides, since it provides the information that line GK bisects line HJ, meaning that they have been split evenly (they have been split, with even/same lengths).
<u><em>So now we have three congruent angles, and two congruent sides. This is enough to prove that ΔGHI is congruent to ΔKJI,</em></u>
<u><em /></u>
I think the answer is (-2,2)
Answer:
250
Step-by-step explanation:
Pretty much every time it asks for the abasloute value it just asks how much to get the zero on the number line. It will ALWAYS be positive. For example -5 will be 5 to get to zero on the numberline. Same thing with a positive 5.
