Answer:
5 more games to be won for the 50% success rate.
Step-by-step explanation:
Total number games played = 500
Number of successful games = 49% of 500
= 500 × ![\frac{49}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B49%7D%7B100%7D)
= 245
Number of successful games for the success of 50% = 500 × ![\frac{50}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B50%7D%7B100%7D)
= 250
Therefore, number of game you have to win more = 250 - 245
= 5 games
A) x + y = 110
x - y = 40
B) Melvin swims for 35 minutes every day.
C) It is not possible
Step-by-step explanation:
Step 1:
Let x denote the duration for which Melvin plays tennis and y denote the duration for which he swims
Step 2 :
Part A :
Given that the total duration for which he plays and tennis is 110 minutes
so we have x + y = 110
Also given that he plays tennis for 40 minutes more than he swims
So, x = y+ 40 =>x-y = 40
So the linear pair of equations are
x + y = 110
x-y = 40
Step 3 :
Part B
Solving the above 2 equations we have
y+40+y = 110 = > 2y+ 40 = 110 = > y = 2y = 70 = >35
x = y+40 = 35+ 40 = 75
So Melvin plays tennis for 75 minutes and swims for 35 minutes every day.
Step 4 :
Part C
Given he plays and swims for 110 mins exactly, i.e x + y = 110
If Melvin plays tennis for 70 minutes , then x = 70, then the time for which he can swim is 110 - 70 = 40 mins.
He gets only 40 mins for swimming which is not 40 mins more than he plays tennis .
So this case is not possible.
Which of the tables represents a function ? Table P 8,3 1,7 5,4 Table Q 9,3 9,5 4,2. Table R 7,2 8,6 7,3. Table S 1,7 1,5 9,2 Ta
babymother [125]
Table P because it is a one-to-one relation.
The other 3 are one-to-many relations (eg table Q maps 9 on to 3 and 9 on to 5)
Just plug in an easy number for "x" and solve. Then see if the second problem is really greater that the first