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Pie
3 years ago
12

Janet wants to solve the equation above, what should she multiply by both sides of this equation by

Mathematics
2 answers:
notsponge [240]3 years ago
7 0

For this case, we must bear in mind that:

y ^ 2-1 = (y + 1) (y-1)

So, if we multiply both sides of the equation by y ^ 2-1 we have:

y (y ^ 2-1) + y ^ 2-5 = \frac {(y ^ 2 + y + 2) (y ^ 2-1)} {y + 1}\\y (y ^ 2-1) + y ^ 2-5 = \frac {(y ^ 2 + y + 2) (y + 1) (y-1)} {y + 1}\\y (y ^ 2-1) + y ^ 2-5 = (y ^ 2 + y + 2) (y-1)

Thus, we must multiply by:

y^ 2-1

Answer:

y ^ 2-1

djyliett [7]3 years ago
5 0

Answer:

y^2 - 1.

Step-by-step explanation:

We multiply by the Lowest Common Denominator of y + 1 and y^2 - 1 which is y^2 - 1.  (Note y^2 - 1 = (y - 1)(y + 1) ).

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