Question

Janet wants to solve the equation above, what should she multiply by both sides of this equation by

Answer 1

For this case, we must bear in mind that:

$y ^ 2-1 = (y + 1) (y-1)$

So, if we multiply both sides of the equation by $y ^ 2-1$ we have:

$y (y ^ 2-1) + y ^ 2-5 = \frac {(y ^ 2 + y + 2) (y ^ 2-1)} {y + 1}\\y (y ^ 2-1) + y ^ 2-5 = \frac {(y ^ 2 + y + 2) (y + 1) (y-1)} {y + 1}\\y (y ^ 2-1) + y ^ 2-5 = (y ^ 2 + y + 2) (y-1)$

Thus, we must multiply by:

$y^ 2-1$

Answer:

$y ^ 2-1$

Answer 2

Answer:

y^2 - 1.

Step-by-step explanation:

We multiply by the Lowest Common Denominator of y + 1 and y^2 - 1 which is y^2 - 1.  (Note y^2 - 1 = (y - 1)(y + 1) ).