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andre [41]
2 years ago
9

i have 5 1/2 yards of fabric and i have 33 students and each students need bandanna. how di work this problem

Mathematics
2 answers:
Akimi4 [234]2 years ago
8 0
Step 1:
Start by setting it up with the divisor 5 on the left side and the dividend 33 on the right side like this:

5 ⟌ 3 3

Step 2:
The divisor (5) goes into the first digit of the dividend (3), 0 time(s). Therefore, put 0 on top:

0
5 ⟌ 3 3

Step 3:
Multiply the divisor by the result in the previous step (5 x 0 = 0) and write that answer below the dividend.

0
5 ⟌ 3 3
0

Step 4:
Subtract the result in the previous step from the first digit of the dividend (3 - 0 = 3) and write the answer below.

0
5 ⟌ 3 3
- 0
3

Step 5:
Move down the 2nd digit of the dividend (3) like this:

0
5 ⟌ 3 3
- 0
3 3

Step 6:
The divisor (5) goes into the bottom number (33), 6 time(s). Therefore, put 6 on top:

0 6
5 ⟌ 3 3
- 0
3 3

Step 7:
Multiply the divisor by the result in the previous step (5 x 6 = 30) and write that answer at the bottom:

0 6
5 ⟌ 3 3
- 0
3 3
3 0

Step 8:
Subtract the result in the previous step from the number written above it. (33 - 30 = 3) and write the answer at the bottom.

0 6
5 ⟌ 3 3
- 0
3 3
- 3 0
3
Which equals 6
Alecsey [184]2 years ago
7 0

Answer:

(1/6 yd)/student

Step-by-step explanation:

Figure out the measure (in yards) that corresponds to each of 33 students:

 5.5 yds            5.5                             55*10^(-1)

------------------- = ------- yds/student = ----------------- yds/student, or

 33 students     33                                33

  5

-------- yd/student, or, finally, 1/6 yd/student

  30

Check:  How much fabric is used to make a bandana for each of 33 students if 1/6 yd is required for each?  (33 students)([1/6] yd/student = 5.5 yd (correct)

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Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

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2 years ago
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