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3 years ago

8

Which of the following is a coefficient in the algebra expression 12p^5+r-16?

1 answer:

Andru [333]3 years ago

8 0

Answer:

12 (or A)

Step-by-step explanation:

A coefficient is the number before a variable.

Examples: 5r , 34y, 10x^2 (the coefficients are 5, 34, and 10)

12 has a variable after it, so 12 is a coefficient.

You might be interested in

What is the compatable number of 358/3

Fudgin [204]

Round 358 to the nearest 5 or 10, which would be 360. 360/3=120 so the compatible number would be 120.

5 0

4 years ago

Evaluate 2x for each value of x. Write your answers in simplest form. Show your work!

Liono4ka [1.6K]

1. 1/2

2.2/3

3. 1

4. 1/3

5. 2/7

6. 1/4

7. 4/3

8. 3/2

<h3>How to evaluate the value</h3>

To find 2x of the vale of x, we have to multiply the value of 'x' by 2

1. x = 1/4

$2x = 2 * \frac{1}{4}$ ⇒ $\frac{2}{4}$ ⇒ $\frac{1}{2}$

2. x = 1/3

$2x = 2 * \frac{1}{3}$ ⇒ $\frac{2}{3}$

3. x = 1/2

$2x = 2* \frac{1}{2}$ ⇒ $\frac{2}{2}$ ⇒ $1$

4. x= 1/6

$2x = 2* \frac{1}{6}$ ⇒ $\frac{2}{6}$ ⇒ $\frac{1}{3}$

5. x = 1/ 7

$2x = 2 * \frac{1}{7}$ ⇒ $\frac{2}{7}$

6. x = 1/8

$2x = 2 * \frac{1}{8}$ ⇒ $\frac{2}{8}$ ⇒ $\frac{1}{4}$

7. x = 2/3

$2x = 2 * \frac{2}{3}$ ⇒ $\frac{4}{3}$

8. x = 3/4

$2x = 2 * \frac{3}{4}$ ⇒ $\frac{6}{4}$ ⇒ $\frac{3}{2}$

Learn more about algebraic expressions here:

brainly.com/question/723406

#SPJ1

6 0

2 years ago

The largest set of x values satisfying

velikii [3]

Answer:

If $p\ge -\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

Step-by-step explanation:

Solve two inequalities for x.

1. $2,018x-p$

Separate terms with x and without x into two sides:

$2,018x-2,020x$

Multiply by -1:

$2x>-2p\\ \\x>-p$

2. $7x+3p$

Separate terms with x and without x into two sides:

$7x-10x$

Multiply by -1:

$3x>2+3p\\ \\x>\dfrac{2}{3}+p$

Find the largest set of x values satisfying both inequalities:

$x>-p\\ \\x>\dfrac{2}{3}+p$

If

$-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p$

then $x>-p$ and $mn=-p=p\cdot (-1),\ m+n=p-1.$ In this case both m and n are negative.

If $p>-\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

If $p=-\dfrac{1}{3},$ then $x>\dfrac{1}{3}$ and $mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}$

7 0

3 years ago

HELP I'M BEING TIMED FOR THIS TEST!!!

ICE Princess25 [194]

The correct answer is C
You must apply the power to both 5 and t

7 0

3 years ago

Please help! it’s angles again

serg [7]

Answer:

115-2*180

= 245

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers