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Diano4ka-milaya [45]
2 years ago
6

If x and y vary directly and x=25 when y=100 find x when y=24. PLEASE HELP FASTTTTTTT

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
6 0

Answer:

x = 6

Step-by-step explanation:

Given that x and y vary directly then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition x = 25 when y = 100 , then

100 = 25k ( divide both sides by 25 )

4 = k

y = 4x ← equation of variation

When y = 24 , then

24 = 4x ( divide both sides by 4 )

6 = x

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The percentage of water in an unknown hydrate was determined by heating the sample and driving the water off the sample. Two ind
Bas_tet [7]

Answer:

It should be reported as 20.648%

Step-by-step explanation:

Since we have 2 different observed values hence we shall use an average of the 2 values to report the result

Thus value is \frac{19.564+21.731}{2}=20.6475%

As we can see that the least count of our observations is upto 3 decimal places hence we have to report a result upto only 3 decimal places thus we need to round off the fourth decimal place thus the digit shall be increased by 1 since we have to drop off 5 and the digit before 5 is 7 which is an odd number.

Thus the result shall be 20.648%

8 0
3 years ago
How do you solve the indicated variable?<br> 6=mx+b for x
UkoKoshka [18]

6 = mx + b \\ 6 - b = mx \\  \frac{6 - b}{m}  = x
6 0
2 years ago
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Point C has a _____ abscissa and a _____ ordinate.
bulgar [2K]

Abcissa is x, and ordinate is y.

In this case the x is positive, and the y is negative.

Therefore, the answer is "positive, negative"

8 0
2 years ago
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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
2 years ago
A variable needs to be eliminated to solve
lesya692 [45]

Answer:

(7, - 7 )

Step-by-step explanation:

- 4x + y = - 35 → (1)

- 2x - y = - 7 → (2)

adding the 2 equations term by term will eliminate the y- term

(- 4x - 2x) + (y - y) = - 35 - 7

- 6x + 0 = - 42

- 6x = - 42 ( divide both sides by - 6 )

x = 7

substitute x = 7 into either of the 2 equations and solve for y

substituting into (1)

- 4(7) + y = - 35

- 28 + y = - 35 ( add 28 to both sides )

y = - 7

solution is (7, - 7 )

6 0
2 years ago
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