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Colt1911 [192]
3 years ago
5

The _____of a segment divides the segment into two segments of equal length.

Mathematics
2 answers:
nexus9112 [7]3 years ago
6 0
The middle of the line segment or the half way mark. Check this out for an example. https://www.chilimath.com/lessons/intermediate-algebra/midpoint-formula/
Cloud [144]3 years ago
5 0
The midpoint of the segment is the answer
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The mod told me to put harder questions so here's a harder question:<br> 2x+12= 24 what is x
Cerrena [4.2K]

Answer:

x=18

Step-by-step explanation:

done

3 0
3 years ago
Read 2 more answers
Select all the expressions that are equivalent to 5x + 30x - 15x
Andrej [43]

Step-by-step explanation:

5(x+6x-3x)

(5+30-15)x

if you open the brackets, it will be 5x+30x-15x

7 0
3 years ago
The graph shows the number of gallons of white paint that were mixed with gallons of blue paint in various different ratios:
nadezda [96]

Answer:

2

Step-by-step explanation:

because it is 2 parts white paint one part blue paint

6 0
3 years ago
Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2
Anastaziya [24]

Answer:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

Step-by-step explanation:

we would like to figure out the derivative of the following:

\displaystyle  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

to do so, let,

\displaystyle y =  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

By simplifying we acquire:

\displaystyle y =  3 -  \frac{2}{x}  -  \frac{1}{ {x}^{2} }

use law of exponent which yields:

\displaystyle y =  3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} }

take derivative in both sides:

\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  (3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} } )

use sum derivation rule which yields:

\rm\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  3 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

By constant derivation we acquire:

\rm\displaystyle  \frac{dy}{dx} =  0 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

use exponent rule of derivation which yields:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ - 1 -1} ) -     ( - 2 {x}^{  - 2 - 1} )

simplify exponent:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ -2} ) -     ( - 2 {x}^{  - 3} )

two negatives make positive so,

\displaystyle  \frac{dy}{dx} =   2 {x}^{ -2} +      2 {x}^{  - 3}

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

\displaystyle  \frac{dy}{dx} =   \frac{2 }{x^2}+       \frac{2}{x^3}

simplify addition:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

and we are done!

5 0
3 years ago
The on-line access computer service industry is growing at an extraordinary rate. Current estimates suggest that only 20% of the
vitfil [10]

Answer:

The probability is 0.4207

Step-by-step explanation:

The probability of a home-based computer having access to on-line services is p = 0.2 (data from the exercise)

Then, the probability of a home-based computer not having access to on-line services is p = 1 - 0.2 = 0.8

We are going to use this probability (p = 0.8) to solve the exercise.

Let's define the random variable X

X : ''Number of home-based computers not having access to on-line services''

X can be modeled as a binomial random variable

X ~ Bi(p,n)

X ~Bi(0.8,25)

Where p is the success probability and n is the number of Bernoulli independent experiments we are taking place.

We are going to count ''a success'' as a computer not having access to on-line services.

The binomial probability function is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as

nCx=\frac{n!}{x!(n-x)!}

p is the success probability and n the number of Bernoulli independent experiments taking place.

In our exercise,

p=0.8\\n=25

We are looking for :

P(X>20)=P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)

P(X>20)=(25C21)0.8^{21}0.2^{4}+(25C22)0.8^{22}0.2^{3}+(25C23)0.8^{23}0.2^{2}+(25C24)0.8^{24}0.2^{1}+(25C25)0.8^{25}0.2^{0}

P(X>20)=0.1867+0.1358+0.0708+0.0236+0.8^{25}

P(X>20)=0.4207

Finally, the probability of finding that more than 20 of 25 home-based computers do not have access to on-line services is 0.4207

6 0
3 years ago
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