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3 years ago

10

Using numbers 12,4,5,17,12 make 24. Helllpppp

1 answer:

romanna [79]3 years ago

4 0

Answer: To get 24

Step-by-step explanation

What you would need to do is first multiply 12 x 5 would come out as 60.

Then from 60 you subtract 17 and 12 to get 5. Divide by the 5 that you just got from 17 and 12 and to get 20. Using the 4 add it to the 20 to get 24.

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Help Anyone please? >>>>>>>>>>>>>>>>>>>>>>>>>>>

denis-greek [22]

Answer:

the answer is c

Step-by-step explanation:

y = 5x

as it says x + y = 10

so one number which is represented as x is times 5 as the other which brimg to our answer y =5x

8 0

3 years ago

Point Lis a centroid of the triangle FWD, If RL = 54 cm, what is RD?

Wittaler [7]

Answer:

RD = 162 cm

Step-by-step explanation:

LD = 2 RL = 2* 54 = 108

RD = RL + LD

RD = 54 + 108

RD = 162 cm

7 0

3 years ago

Find length,width and area<br><br>plus bonus<br><br>please show work

stira [4]

A square with the same perimeter as a rectangle will have larger area.

However, 42 is not divisible by 4, so we can do 10 by 11.

Length = 11, Width = 10, Area = 110

42 / 4 = 10.5

Length and Width = 10.5, Area = 110.25

3 0

3 years ago

What is the value of x

il63 [147K]

the 2 angles are congruent so...

x+40=3x set the 2 equations equal to each other

40=2x subtract x from both sides

20=x divide by 2

x=20 is the final answer

Have a blessed day!

5 0

3 years ago

Read 2 more answers

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

4 years ago