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2 years ago

A circular foundation has a radius of 9.4 feet. Find it's diameter and circumference to the nearest tenth

Mathematics

2 answers:

Ganezh [65]2 years ago

5 0

The diameter of the circular foundation would be 18.8 feet, and the circumference would be 59.1 feet.

Alexandra [31]2 years ago

5 0

The diameter in a circle is twice the radius which is 18.8 in this situation.

Circumference is 2 * π * r

just substitute the values In geometry they use 3.14 for pi sometimes
so it would be 2 * 3.14* 9.4
= 59.03

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Amy filled bags with mixed nuts. The weights of the bags are 1/8 lb, 1/4 lb, 1/8 lb, 1/2 lb, 1/8 lb, 1/4 lb, 1/8lb, 1/2 lb, 1/8

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(a)See attached

(b) $\text{Average Weight =}\dfrac{1}{4}$ lb$

Step-by-step explanation:

The weights of the bag are given below:

$1/8 lb, 1/4 lb, 1/8 lb, 1/2 lb, 1/8 lb, 1/4 lb, 1/8lb, 1/2 lb \\1/8 lb, 1/4 lb, 1/8 lb, 1/2 lb, 1/8 lb, 1/8 lb, 1/4 lb, 1/2 lb.$

When sorted, we have:

$1/8 lb, 1/8 lb, 1/8lb, 1/8 lb, 1/8 lb, 1/8 lb, 1/8 lb, 1/8 lb\\ 1/4 lb,1/4 lb, 1/4 lb, 1/4 lb\\ 1/2 lb, 1/2 lb, 1/2 lb,1/2 lb,$

8 bags weigh $\frac{1}{8}lb$
4 bags weigh $\frac{1}{4}lb$

4 bags weigh $\frac{1}{2}lb$

Part A

See attached for the Line plot

Part B

Average Weight of the bags

$=\dfrac{(8X\dfrac{1}{8})+ (4X\dfrac{1}{4})+(4X\dfrac{1}{2})}{16} \\=\dfrac{1+1+2}{16}\\=\dfrac{4}{16}\\$Average Weight =\dfrac{1}{4}$ lb$

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