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3 years ago

Question 2 Unsaved Simplify. 3c812c12

Mathematics

1 answer:

seropon [69]3 years ago

4 0

I think the answer would be that the dimplified form of 3c8/12c12 is
c^20
———
4

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What is the percent decrease from 95 to 19?

serious [3.7K]

Answer:

-80 percent

Step-by-step explanation:

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3 years ago

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10x - 6 = 3(5 + x) true?

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True

Step-by-step explanation:

I think i am correct dear

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2 years ago

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Notebooks cost $ 1.20 each. This weekend they will be on sale for $ 0.80. What percentage is the sale

Rainbow [258]

From the information we have, we know that each book costs 1.20 dollars. So we shall say this price is at 100% .

Now we need to form an equation to get the percentage when the books are sold at 0.80 dollars.

100% = 1.20

x = 0. 80

Where x is the new percentage when the sale is at 0.80 dollars.

We cross multiply the equation:

1.20 *x = 0.80 * 100

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x = 80/1.2

x = 66.7%

Round off 66.7 to the nearest tenth we get 67%

The notebooks are sold at 67% (of the original cost).

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3 years ago

The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150

tiny-mole [99]

Answer:

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150 indicated that the primary reason for setting up the plan was tax related.

This means that $n = 200, \pi = \frac{150}{200} = 0.75$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.}{2} = 0.975$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.6996$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.8004$

As percent:

0.6996*100% = 69.96%

0.8004*100% = 80.04%.

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

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3 years ago

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

boyakko [2]

Answer:

Step-by-step explanation:

y=59(0.59)ˣ

As the number under the exponent is less than 1, this is a decay function.

Value of y will be decreased by (1.00 - 0.59)100 = 41% for each unit increase in x.

3 0

3 years ago