Answer:
I believe it would be 21 units . dont let extra line's confuse you just pay attention to the letters its asking for
A negative times a negative is a positive. I am not sure if that's the question, but hopefully that helps if it was.
Probablity=desiredoutcomes/totalpossibleoutcomes
total possible outcomes=1+2+4+3=10
desired outcomes=4 blue
probablity=4/10=2/5=40%
Answer:
We use Baye's theorem: P(A)P(B|A) = P(B)P(A|B)
with (A) being defective and
(B) marked as defective
we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)
Since P(A) = 0.1 and P(B|A)=0.9,
P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9
and
P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15
put these values in eq(2)
P(B) = (0.1 × 0.9) + (0.9 × 0.15)
= 0.225 put this in eq(1) and solve for P(B)
P(B) = 0.4
I don’t know if this correct or not but I think it’s 1,666
