C(24,3) which means the number of combinations of 24 cans taken 3 at a time.
C( 24, 3) = 2024
24! divided by the product of (3! * 21!)
Let y = 3^x , then 9^x = (3^2)^x = (3^x)^2 = y^2, so we can write the equation as
y^2 - 10y + 9 = 0
(y - 9)(y - 1) = 0
giving y = 9 or y = 1
Therefore 3^x = 9 giving x = 2
and 3^x = 1 giving x = 0
so the solution set is {0, 2}
Note - I have assumed that the 'x' after the 10 means 'multiply'. Is that correct?
Let x be the total money she had
So x-45.32=32.25
□ x =45.32+32.25
Answer:
The total cost of her lunch is $14.65
Step-by-step explanation:
15% of $12.74 is $1.91
12.74+1.91=14.65
It would be the second one if you follow PEMDAS
