number 5 is not and number 7 is a function because every input has exactly one output
Answer:
D
Step-by-step explanation:
Because the theoretical probability is greater than the experimental probability
The sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.
<h3>What is a cube?</h3>
It is defined as three-dimensional geometry that has six square faces and eight vertices.
We have a volume of a cubical box is 54.872 cm³
V = 54.872 cm³
As we know the volume of the cube:
V = side³
54.872 = side³
Taking cube root on both sides:
side = 3.8 cm
Thus, the sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.
Learn more about the cube here:
brainly.com/question/15420947
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<h3>
Answer: 1/8</h3>
In decimal form, 1/8 = 0.125 which converts to 12.5%
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Work Shown:
The 63 should be 6^3. There are 6 choices per slot, and 3 slots, so 6^3 = 216 different outcomes.
Here are all of the ways to add to 11 if we had 3 dice
- sum = 1+4+6 = 11
- sum = 1+5+5 = 11
- sum = 1+6+4 = 11
- sum = 2+3+6 = 11
- sum = 2+4+5 = 11
- sum = 2+5+4 = 11
- sum = 2+6+3 = 11
- sum = 3+2+6 = 11
- sum = 3+3+5 = 11
- sum = 3+4+4 = 11
- sum = 3+5+3 = 11
- sum = 3+6+2 = 11
- sum = 4+1+6 = 11
- sum = 4+2+5 = 11
- sum = 4+3+4 = 11
- sum = 4+4+3 = 11
- sum = 4+5+2 = 11
- sum = 4+6+1 = 11
- sum = 5+1+5 = 11
- sum = 5+2+4 = 11
- sum = 5+3+3 = 11
- sum = 5+4+2 = 11
- sum = 5+5+1 = 11
- sum = 6+1+4 = 11
- sum = 6+2+3 = 11
- sum = 6+3+2 = 11
- sum = 6+4+1 = 11
There are 27 ways to add to 11 using 3 dice. This is out of 216 total outcomes of 3 dice being rolled.
So, 27/216 = (1*27)/(8*27) = 1/8 is the probability of getting 3 dice to add to 11.
Answer:
w^2*(w+4)*(w^2+10)
Step-by-step explanation:
w^5+4w^4+10w^3+40w^2
w^2*(w^3+4w^2+10w+40)\w^2*(w^2*(w+4)+10(w+4))
w^2*(w+4)*(w^2+10)
