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4 years ago

What is 5.6 = p - 8.3

Mathematics

1 answer:

vredina [299]4 years ago

7 0

Answer:

p - 8.3 = 5.6

p = 5.6+8.3= 13.9

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At Fireflies Kids Camp, 4 out of the 10 kids in the yellow cabin are taking swimming lessons. In the blue cabin, 5 out of the 15

fenix001 [56]

Answer:

Both cabins do not have the same ratio of swimmers to total kids.

Step-by-step explanation:

The ratio of swimmers to total kids in the yellow cabin is:

4 : 10

The ratio of swimmers to total kids in the blue cabin is:

5 : 15

4 : 10 and 5 : 15 are not equivalent ratios because:

LCM of 10 and 15 is 30

Multiply each term in a ratio by a number so that the second term is 30:

4 x 3 = 12

10 x 3 = 30

4 : 10 = 12 : 30

5 x 2 = 10

15 x 2 = 30

5 : 15 = 10 : 30

12 : 30 and 10 : 30 are NOT the same ratios.

Hope this helps!

4 0

3 years ago

Simplify y / 3 - x / 4 / x / 6 + y / 8

s2008m [1.1K]

Wait is there any other information?

4 0

3 years ago

you went out to eat with 3 friends and your meal cost 72.50 how much was the bill if 6.75 sale taxes was included

dimulka [17.4K]

Answer:

$29.67 each

Step-by-step explanation:

6.75% of $72.50 = $4.90

72.50 + 4.90 = $77.40

15% of 77.40 = 11.61

77.40 + 11.61 = 89.01

89.01 divided by 3 = $29.67 each

3 0

3 years ago

Find area of the isosceles triangle formed by the vertex and the x-intercepts of parabola y=x2+4x−12.

xz_007 [3.2K]

The area of the isosceles triangle is 64 sq units.

<u>Solution:</u>

Part 1: x-intercepts

The x-intercepts occur at the points on the function where y=0

So, we need to solve

$x^2-4x-12=0$

The left side factors fairly easily into:

$(x-6)(x+2)=0$

So solution occur when

$x-6=0\rightarrow x=6$

and

$x+2=0\rightarrow x=(-2)$

So the x-intercepts are at (0,6) and (0,−2)

Part 2: vertex of the parabola

The vertex of a simple quadratic parabola occurs when the derivative of the quadratic is equal to 0.

The derivative of the given quadratic is

$\frac{dy}{dx}=2x-4$

By observation, this is equal to 0 when x=2

When x=2 the original equation becomes

$y=(2)^2-4(2)-12$

$y=-16$

Therefore the vertex of this parabola is at (2,−16)

The endpoints of the base of the isosceles triangle are (-6, 0) and (2, 0)

$\Rightarrow$ so its base is 8

The height of the triangle reaches from the midpoint of the base (-2, 0) and the vertex (2, -16)

$\Rightarrow$ so its height is 16

The area is $\frac{1}{2}\times \text { base }\times \text { height }=\frac{1}{2}\times8\times16=64 \text{ sq units }$

6 0

3 years ago

Find a solution to the linear equation y=6x−18 by filling in the boxes with a valid value of x and y.

juin [17]

You can choose any value for x and find the corresponding y value. So let’s assume x=1.

y=6x-18
y=6(1)-18
y=6-18
y=-12

So a correct ordered pair would be (1,-12).

7 0

3 years ago