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4 years ago

-12x^5/(2x+5)1/2help plz

Mathematics

1 answer:

yuradex [85]4 years ago

5 0

Answer:

6x^5/2x+5

Step-by-step explanation:

12x^5/(2x+5)1/2

reduce the numbers with greatest common divisor

greatest common divisor: 2

6x^5/2x+5

i hope this helps!

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8y=3x solve for y x-y+2g=5g b=ay solve a b-c/3=a solve for b

Llana [10]

I hope I am right. here you go:)

3 0

3 years ago

please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.

likoan [24]

ANSWER:

$\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4$

STEP-BY-STEP EXPLANATION:

We have the following equation:

$f(x)=\sqrt{x}-4$

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

$\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\ \\ \sqrt{f^{-1}(x)}=x+4 \\ \\ f^{-1}(x)=(x+4)^2 \end{gathered}$

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

$\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4$

4 0

1 year ago

NEED HELP WILL MARK BRAINLEST

Marina CMI [18]

Answer:

103.27 degree

Step-by-step explanation:

You need to find the angle of the interior of the triangle first, and then find the exterior. Hope I helped!

3 0

3 years ago

Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

Hence, (-1,5) is on the graph

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

(1,0) is not on the graph because g(x) is not equal to 0

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

Hence, $(3, \frac{1}{125})$ is on the graph

D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

Hence, $(-2, \frac{1}{25})$ is not on the graph

8 0

4 years ago

How to get slope from standard form.

lidiya [134]

Answer:

Solve the equation for y. See example.

Step-by-step explanation:

I'll use 3x + 5y = 15. First subtract 3x from both sides since it is positive.

$3x + 5y = 15 \\ - 3x \: \: \: \: \: \: \: \: \:\: \: \: \: \: \: - 3x$

$5y = - 3x + 15$

Now solve for y by dividing each term by 5.

$\frac{5y}{5} = \frac{ - 3}{5} x + \frac{15}{5}$

Now simplify.

$y = \frac{ - 3}{5} x + 3$

The slope is

$- \frac{3}{5}$

5 0

3 years ago