The probability that a train leaves on time is .07. The probability that the train arrives on time and leaves on time is 0.56. W
hat is the probability that the train arrives on time, given that it leaves on time?
2 answers:
Refer to the other answer.
Event A: leave on time P(A) = 0.7
Event B: arrive on time P(B) = ?
Both: P(A)*P(B) = 0.56 -> P(B) = 0.8
I'm assuming you are typing the number wrong for event A
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