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Lesechka [4]
3 years ago
13

A. A frog is climbing out of a well that is 8 feet deep. The frog can climb 4 feet per

Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer:

A: 5 hrs.   B: 14 hrs. and 40 min.

Step-by-step explanation:

too long to explain.

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Hello : 
2145 = 11×13×3×5 ( prime factorisation  product)
2145 = 11×13×15
the <span>three consecutive odd numbers whose product is 2145 are : 11 , 13 ,15</span>
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Please Help. &gt;.&lt;<br><br> Is This True Or False?
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False

Step-by-step explanation

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If nine is X percent of 45, what is X percent of 5
antoniya [11.8K]

Answer:

x percent of 5 is 1

Step-by-step explanation:

Nine is x percent of 45

x = 20

20 % of 5 = 1

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4 years ago
Analyze the diagram below and complete the instructions that follow.
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D. Angel 6 because vertical is just asking what angle is on the other side of angle 3
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3 years ago
A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require
Aleksandr-060686 [28]

Answer:

r\approx 1.084\ feet

h\approx 1.084\ feet

\displaystyle A=11.07\ ft^2

Step-by-step explanation:

<u>Optimizing With Derivatives </u>

The procedure to optimize a function (find its maximum or minimum) consists in :

  •  Produce a function which depends on only one variable
  •  Compute the first derivative and set it equal to 0
  •  Find the values for the variable, called critical points
  •  Compute the second derivative
  •  Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 ft^3. The volume of a cylinder is given by

\displaystyle V=\pi r^2h

Equating it to 4

\displaystyle \pi r^2h=4

Let's solve for h

\displaystyle h=\frac{4}{\pi r^2}

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

\displaystyle A=\pi r^2+2\pi rh

Replacing the formula of h

\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )

Simplifying

\displaystyle A=\pi r^2+\frac{8}{r}

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

\displaystyle A'=2\pi r-\frac{8}{r^2}=0

Rearranging

\displaystyle 2\pi r=\frac{8}{r^2}

Solving for r

\displaystyle r^3=\frac{4}{\pi }

\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet

Computing h

\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

\displaystyle A''=2\pi+\frac{16}{r^3}

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.

The minimum area is

\displaystyle A=\pi(1.084)^2+\frac{8}{1.084}

\boxed{ A=11.07\ ft^2}

8 0
3 years ago
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